Rates of change (1 Viewer)

[hscishard]

Need help with this question

 

[MetroMattums]

Is the answer to part one -2sin(arccosx)?

 

[hscishard]

Is the answer to part one -2sin(arccosx)?

Haven't learnt inverse trig functions..
But it might be right.

-2(root[1-x^2])

 

[random-1006]

Need help with this question

i think i got it lol, its good question

 

[MetroMattums]

Haven't learnt inverse trig functions..
But it might be right.

-2(root[1-x^2])

Whoops haha it simplifies to that.

The first thing you have to do is get the parametric function:

x = cosø
dx/dt = -(dø/dt)sinø
dx/dt = -(dø/dt)√(1-x^2)

Then you have to work out dø/dt, which is angular velocity.

Given tangential velocity = 2 m/s
Period T = (2π)/2 = π

But you know angular velocity w = 2π/T
So w = 2π/π = 2 = dø/dt

ie. dx/dt = -2√(1-x^2)

 

[random-1006]

Haven't learnt inverse trig functions..
But it might be right.

-2(root[1-x^2])

this is correct

 

[hscishard]

Gotta wait till the start of year 12 to do this question