MedVision ad

T formulae questions (2 Viewers)

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
lyounamu said:
Yeah. On top, you should get cos^2(7.5) because 1-sin^2(x) = cos^2(x)
And on the bottom you should have sec^(x) because 1+tan^2(x) = sec^2(x). :D
the top should be like 4(tan 7.5)(1-tan^2(7.5)) right? can you guide me through it please? do you change the tan^2(7.5) to like sec^2(7.5) - 1 and proceed from there?

goshh do each question need this kind of working out? its huge!
 

lolokay

Active Member
Joined
Mar 21, 2008
Messages
1,015
Gender
Undisclosed
HSC
2009
clintmyster said:
i know that but how do you use that in this scenario..i dont see many ways of making this in terms of sin unless you convert tan...is this question supposed to be hard? its supposedly the "easier" questions in yr12 3u!
the question is 2tan15/(1+tan^2 15) , and sin@ = 2t/(1+t^2), where t = tan @/2

so let tan @/2 = tan15, @ = 30

therefore 2tan15/(1+tan^2 15) = sin30 = 1/2

this is definitely an easy question since its just sub'ing into the t formula for sin@
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
clintmyster said:
the top should be like 4(tan 7.5)(1-tan^2(7.5)) right? can you guide me through it please? do you change the tan^2(7.5) to like sec^2(7.5) - 1 and proceed from there?

goshh do each question need this kind of working out? its huge!
I will do it again. I am a bit confused now. Because I am doing two questions simultaneously (from another thread).
 

midifile

Na Na Na Na Naa
Joined
Oct 11, 2006
Messages
1,143
Location
Sydney
Gender
Female
HSC
2008
clintmyster said:
i know that but how do you use that in this scenario..i dont see many ways of making this in terms of sin unless you convert tan...is this question supposed to be hard? its supposedly the "easier" questions in yr12 3u!
Rather than making t = tan (7.5) let t = tan 15.
therefore 2tan15/1+tan^2(15) = 2t/1+t^2
= sin(2x15) (using the sin t-formula)
= sin30
=1/2
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
lolokay said:
the question is 2tan15/(1+tan^2 15) , and sin@ = 2t/(1+t^2), where t = tan @/2

so let tan @/2 = tan15, @ = 30

therefore 2tan15/(1+tan^2 15) = sin30 = 1/2

this is definitely an easy question since its just sub'ing into the t formula for sin@
I thought this question was supposed to be "prove". Damn! Why did I even go further when I didn't need to?
 

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
lolokay said:
the question is 2tan15/(1+tan^2 15) , and sin@ = 2t/(1+t^2), where t = tan @/2

so let tan @/2 = tan15, @ = 30

therefore 2tan15/(1+tan^2 15) = sin30 = 1/2

this is definitely an easy question since its just sub'ing into the t formula for sin@
what im still not getting is why did you choose to sub the angle in sin @...why not cos? how did that come about?
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
clintmyster said:
what im still not getting is why did you choose to sub the angle in sin @...why not cos? how did that come about?
If you look at the question closely, it resembles

2t/(1+t^2)

where t = tan15 (which is tan 30/2)
Therefore, the answer is basically sin 30.
 

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
lyounamu said:
If you look at the question closely, it resembles

2t/(1+t^2)

where t = tan15 (which is tan 30/2)
Therefore, the answer is basically sin 30.
oh that makes a lot of sense now! does that mean for like 4f) it resembles tan and 3b,d) sine again?
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
clintmyster said:
oh that makes a lot of sense now! does that mean for like 4f) it resembles tan and 3b,d) sine again?
Yeah. I thought they were "prove" questions. Otherwise, they are just too simple that you only write like 2 lines and finish.
 

lolokay

Active Member
Joined
Mar 21, 2008
Messages
1,015
Gender
Undisclosed
HSC
2009
lyounamu said:
I thought this question was supposed to be "prove". Damn! Why did I even go further when I didn't need to?
well, even if it was a prove question you could have made things easier by proving that sin@ = 2t/(1 + t^2). though wouldn't you be able to use the t identities in a proof?
 

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
lyounamu said:
Yeah. I thought they were "prove" questions. Otherwise, they are just too simple that you only write like 2 lines and finish.
i got proving ones coming up but like how hard could they be? this is my very last question i gotta do. just steps to guide me through it will be enough i think?

 

midifile

Na Na Na Na Naa
Joined
Oct 11, 2006
Messages
1,143
Location
Sydney
Gender
Female
HSC
2008
clintmyster said:
i got proving ones coming up but like how hard could they be? this is my very last question i gotta do. just steps to guide me through it will be enough i think?

on the lhs sub (1+t^2)/(2t) for cosec@ and 1-t^2/2t for cot@ and then get rid of the fractions by multiplying top and bottom by 2t. It should rearrange to (1+t)/(1-t)
 

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
i got the LHS alright but with the rhs do you sub in 2t/1-t^2 for tan1/2@?


edit: nevermind i am realy acting stupid today not seeing simple things like that tan1/2@ becomes t omgg...this is like the only trig i dont like LOLL..its in my way of a perfect score grrr!
 

midifile

Na Na Na Na Naa
Joined
Oct 11, 2006
Messages
1,143
Location
Sydney
Gender
Female
HSC
2008
clintmyster said:
i got the LHS alright but with the rhs do you sub in 2t/1-t^2 for tan1/2@?
No. t=tan (1/2@), so if you have (1+t)/(1-t), you can sub in t=tan(1/2@) which gives you 1+tan(1/2@)/1-tan(1/2@)
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
lolokay said:
well, even if it was a prove question you could have made things easier by proving that sin@ = 2t/(1 + t^2). though wouldn't you be able to use the t identities in a proof?
Lol, ok.

Well, my brain is not functioning well today. I had an exam today, that's probably why. :mad:
 

midifile

Na Na Na Na Naa
Joined
Oct 11, 2006
Messages
1,143
Location
Sydney
Gender
Female
HSC
2008
clintmyster said:
edit: nevermind i am realy acting stupid today not seeing simple things like that tan1/2@ becomes t omgg...this is like the only trig i dont like LOLL..its in my way of a perfect score grrr!

Lol. Once you become confident with t-formulas youll be okay. When I first did them I was shit at those prove questions, but you just have to practice them and eventually it will become second nature.:p
 

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
midifile said:
No. t=tan (1/2@), so if you have (1+t)/(1-t), you can sub in t=tan(1/2@) which gives you 1+tan(1/2@)/1-tan(1/2@)
yeah i see all that now..s many mediocre mistakes in this...and its not even remotely challenging or hard to get my head around..maybe i dont feel like doing this or something

anyways guys thanks heaps for the help..clarified a few things for me which i didnt actually realise and yeah =]
 

midifile

Na Na Na Na Naa
Joined
Oct 11, 2006
Messages
1,143
Location
Sydney
Gender
Female
HSC
2008
lyounamu said:
Lol, ok.

Well, my brain is not functioning well today. I had an exam today, that's probably why. :mad:
:( What you were doing was right you just did it for the wrong question :p Hope your brain feels better tomorrow
 

clintmyster

Prophet 9 FTW
Joined
Nov 12, 2007
Messages
1,067
Gender
Male
HSC
2009
Uni Grad
2015
lyounamu said:
Lol, ok.

Well, my brain is not functioning well today. I had an exam today, that's probably why. :mad:
was it a math exam? howd you go?
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top