Trial Results and Papers (1 Viewer)

Nooblet94

Premium Member
Joined
Feb 5, 2011
Messages
1,044
Gender
Male
HSC
2012
I've got the Baulko MX2 trial, but it's hard copy. I can scan it if people desperately want it.

None of mine are really worth uploading - maffs was easy, physics has my horrible scrawls all over it, we used the independant paper for music and we didn't get the paper back for english. I'll type up the essay questions for legal if people want them though.
 

4025808

Well-Known Member
Joined
Apr 2, 2009
Messages
4,377
Location
中國農村稻農
Gender
Male
HSC
2011
Uni Grad
2017
I've got the Baulko MX2 trial, but it's hard copy. I can scan it if people desperately want it.

None of mine are really worth uploading - maffs was easy, physics has my horrible scrawls all over it, we used the independant paper for music and we didn't get the paper back for english. I'll type up the essay questions for legal if people want them though.
How was the Baulko MX2 trial this year? Harder compared with other years?
 

Nooblet94

Premium Member
Joined
Feb 5, 2011
Messages
1,044
Gender
Male
HSC
2012
Alright, so I'm about halfway through and it's moderately hard. However, I have been drinking, so that may be why. I'll scan/upload it tomorrow arvo if I get time and y'all can see for yourselves
 

Nooblet94

Premium Member
Joined
Feb 5, 2011
Messages
1,044
Gender
Male
HSC
2012
Scanner's being a bitch, but I'll type up some of the more interesting ones.

<a href="http://www.codecogs.com/eqnedit.php?latex=\\ $In the Argand Diagram, OPQ is an equilateral triangle. P represents the complex number $z$ and Q represents the complex number $w.\\ $Show that $w^3@plus;z^3=0\\ ~\\ $If $f(xy)=f(x)@plus;f(y)$ for all $x,y\neq 0, $ prove that:$\\ (i)f(x^3)=3f(x)\\ (ii)f(1)=f(-1)=0\\ (iii)f(x)$ is an even function$" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\\ $In the Argand Diagram, OPQ is an equilateral triangle. P represents the complex number $z$ and Q represents the complex number $w.\\ $Show that $w^3+z^3=0\\ ~\\ $If $f(xy)=f(x)+f(y)$ for all $x,y\neq 0, $ prove that:$\\ (i)f(x^3)=3f(x)\\ (ii)f(1)=f(-1)=0\\ (iii)f(x)$ is an even function$" title="\\ $In the Argand Diagram, OPQ is an equilateral triangle. P represents the complex number $z$ and Q represents the complex number $w.\\ $Show that $w^3+z^3=0\\ ~\\ $If $f(xy)=f(x)+f(y)$ for all $x,y\neq 0, $ prove that:$\\ (i)f(x^3)=3f(x)\\ (ii)f(1)=f(-1)=0\\ (iii)f(x)$ is an even function$" /></a>
 

Uniqueness

Member
Joined
Feb 12, 2011
Messages
352
Gender
Undisclosed
HSC
N/A
Scanner's being a bitch, but I'll type up some of the more interesting ones.

<a href="http://www.codecogs.com/eqnedit.php?latex=\\ $In the Argand Diagram, OPQ is an equilateral triangle. P represents the complex number $z$ and Q represents the complex number $w.\\ $Show that $w^3@plus;z^3=0\\ ~\\ $If $f(xy)=f(x)@plus;f(y)$ for all $x,y\neq 0, $ prove that:$\\ (i)f(x^3)=3f(x)\\ (ii)f(1)=f(-1)=0\\ (iii)f(x)$ is an even function$" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\\ $In the Argand Diagram, OPQ is an equilateral triangle. P represents the complex number $z$ and Q represents the complex number $w.\\ $Show that $w^3+z^3=0\\ ~\\ $If $f(xy)=f(x)+f(y)$ for all $x,y\neq 0, $ prove that:$\\ (i)f(x^3)=3f(x)\\ (ii)f(1)=f(-1)=0\\ (iii)f(x)$ is an even function$" title="\\ $In the Argand Diagram, OPQ is an equilateral triangle. P represents the complex number $z$ and Q represents the complex number $w.\\ $Show that $w^3+z^3=0\\ ~\\ $If $f(xy)=f(x)+f(y)$ for all $x,y\neq 0, $ prove that:$\\ (i)f(x^3)=3f(x)\\ (ii)f(1)=f(-1)=0\\ (iii)f(x)$ is an even function$" /></a>
^^^ Nice. Very interesting...
 

someth1ng

Retired Nov '14
Joined
Sep 18, 2010
Messages
5,558
Location
Adelaide, Australia
Gender
Male
HSC
2012
Uni Grad
2021
Y BARELY ANY TRIAL PAPERS? :(

I want to find some papers for legal studies though... *sigh*
People like Beaconite are cheap and just keep promising that they'll give out their papers but all they do is download any papers posted up.
 

zeebobDD

Member
Joined
Oct 23, 2011
Messages
414
Gender
Male
HSC
2012
i've got independent chem clean version but physics written all over
 

btx3

Active Member
Joined
Apr 28, 2012
Messages
385
Gender
Male
HSC
2012
Uni Grad
2018
People like Beaconite are cheap and just keep promising that they'll give out their papers but all they do is download any papers posted up.
yes Beaconite is a cunt
 

hernameisnoelle

New Member
Joined
Feb 4, 2010
Messages
27
Gender
Female
HSC
2012
I only really like my English mark/rank. The rank isn't that great but if you knew what it was before...

Does anyone have any trial papers for Business Studies? It's a new syllabus so I'm having difficulties in finding some :(
 

Scarlet Tears

New Member
Joined
Dec 4, 2011
Messages
19
Gender
Female
HSC
2012
Can some one please tell me if its possible to get 95 with these marks/ranks? The marks are averages for all tests during the year and out of 100. I don't know what my school is ranked but its not in the top 100.
English Advanced: 2nd of 52, 91%
English Extension One: 3rd of 11, 86%
English Extension Two: 2nd of 3, 78%
Chemistry: 1st of 7, 62%
Mathematics: 6th of 14, 69%
Studies of Religion One: 4th of 40, 74%
Legal Studies: 2nd of 13, 89%
 

someth1ng

Retired Nov '14
Joined
Sep 18, 2010
Messages
5,558
Location
Adelaide, Australia
Gender
Male
HSC
2012
Uni Grad
2021
Can some one please tell me if its possible to get 95 with these marks/ranks? The marks are averages for all tests during the year and out of 100. I don't know what my school is ranked but its not in the top 100.
English Advanced: 2nd of 52, 91%
English Extension One: 3rd of 11, 86%
English Extension Two: 2nd of 3, 78%
Chemistry: 1st of 7, 62%
Mathematics: 6th of 14, 69%
Studies of Religion One: 4th of 40, 74%
Legal Studies: 2nd of 13, 89%
The mark itself does not matter, however, you really should be getting higher marks than that at the school that is average ranked. You can probably get 95 but since the school rank is so vague, it's difficult to give a good estimate.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top