d/dx(tanx)=sec^xXcarvengerX said:And what is auxiliary method?
Where do you put the sec2 b? I still can't see it...
and my friend you can always ask questions it is not a problem and i am sorry if i have made you confused. i have written an example of implicit differentiation
e.g. lny=x
1/y*dy/dx=1
dy/dx=y
but y=e^x
hence dy/dx=e^x