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I am sure I saw a program that converts handwriting into LaTeX.Is the domain restricted or do you want a general answer? The reason is I don't want to spend half an hour typing something in latex (I'm very unfluent) if that's not the answer you're looking for![]()
You can't just divide both sides by sinx because you remove the solution sinx=0. As a general rule, you shouldn't divide by a function of x unless you know that x=0 isn't a solution.actually nvm
for the second question:
sin2x=tanx
2sinxcosx=sinx/cosx
2cosx=1/cosx just divided both sides by sinx
2cos^2x=1
let cosx=u
therefore
2u^2=1
u=plus and minus(√2/2)
cosx=plus and minus(√2/2)
solve for x
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^^You can't just divide both sides by sinx because you remove the solution sinx=0. As a general rule, you shouldn't divide by a function of x unless you know that x=0 isn't a solution.
this is the same guy, capperCould someone please show me the working out for these questions?
1.sin3x =sin2x
2. sin2x=tanx
3. tan(a - pi/3) = -3
4. sin 4x-sin2x=0
5. cos3x = cosx
6. 3tan2x = 2tanx
My badYou can't just divide both sides by sinx because you remove the solution sinx=0. As a general rule, you shouldn't divide by a function of x unless you know that x=0 isn't a solution.
A neater way to do the first one is to do:
sin3x-3in2x=0
2cos(5x/2)sin(x/2)=0 (factorising)
cos(5x/2)=0 or sin(x/2)=0
x=(pi+2kpi)/5 or x=2kpi for integers k
Hahahaha you're back on green bar!this is the same guy, capper
I was stuck on 1 bar for quite awhile as well....Dude, ive been stuck on one bar forever!
EDIT:
Im on two now!