VCE Maths questions help (1 Viewer)

[1729]

is the answer 1/sqrt(3) x + 5 ?

That isn't an equation.

 

[boredsatan]

That isn't an equation.

y = 1/sqrt(3) x + 5 ?

 

[InteGrand]

y = 1/sqrt(3) x + 5 ?

Correct!

 

[boredsatan]

No

y = 1/sqrt(3) x + 5
3y = √(3) x + 15
are these the same?

 

[InteGrand]

y = 1/sqrt(3) x + 5
3y = √(3) x + 15
are these the same?

Yes

 

[boredsatan]

Yes

Thanks!
And was just wondering, is ancient orator your custom title?

 

[leehuan]

Thanks!
And was just wondering, is ancient orator your custom title?

You get that after a sufficient amount of posts.

 

[boredsatan]

does maths tend to get a lot harder throughout year 11?

 

[boredsatan]

does maths tend to get a lot harder throughout year 11?

any thoughts?

 

[boredsatan]

any thoughts?

Anyone?

 

[boredsatan]

Bump!
How do know what shape to draw a graph based on the equation?

 

[InteGrand]

Bump!
How do know what shape to draw a graph based on the equation?

You should know the shapes of the graphs of some standard functions. For other ones, you can sketch them with the help of calculus to find turning points and so on. There is a ''curve-sketching recipe'' in some textbooks (like one of the Pender ones) that you can have a look at, or find online.

 

[boredsatan]

What is a rational root?

 

[boredsatan]

What is a rational root?

Anyone, it's really urgent, have an application task on monday

 

[1729]

What is a rational root?

 

[boredsatan]

Can you please elaborate on that?

 

[boredsatan]

How do you find the image of 0 for 3x^2 + 2

 

[InteGrand]

How do you find the image of 0 for 3x^2 + 2

Sub. x = 0 into the expression.

 

[boredsatan]

Sub. x = 0 into the expression.

so if it was the image of 4, sub 4 in the equation, etc

 

[InteGrand]

so if it was the image of 4, sub 4 in the equation, etc

Yeah