VCE Maths questions help (2 Viewers)

[boredsatan]

y = √(-3x+5), how would you find the inverse of this equation?

 

[boredsatan]

y = √(-3x+5), how would you find the inverse of this equation?

Anyone?

 

[InteGrand]

y = √(-3x+5), how would you find the inverse of this equation?

Anyone?

Write x in terms of y. Square both sides as the first step. And make sure to state the correct domain.

 

[boredsatan]

y = 2√(x+1) - 4
what would the endpoint of this equation be?
What would the domain and range be?

 

[1729]

y = 2√(x+1) - 4
what would the endpoint of this equation be?
What would the domain and range be?

 

[boredsatan]

How did you find the endpoint?

 

[leehuan]

How did you find the endpoint?

You can't square root a negative

If x<-1 then you square root a negative. So the endpoint is at x=-1

Also, the domain should be x≥-1 and range y≥-4, i.e. the inequalities should not be strict

 

[boredsatan]

You can't square root a negative

If x<-1 then you square root a negative. So the endpoint is at x=-1

Also, the domain should be x≥-1 and range y≥-4, i.e. the inequalities should not be strict

so would y = 2√(x+4) - 5 have an endpoint of (-4,-5)?

 

[InteGrand]

so would y = 2√(x+4) - 5 have an endpoint of (-4,-5)?

Yes

 

[kawaiipotato]

so would y = 2√(x+4) - 5 have an endpoint of (-4,-5)?

You can work it out for yourself in the future.

 

[boredsatan]

would the inverse of y = √(-3x+5) be y = (x^2-5)/-3

 

[boredsatan]

sketch the function g(x) = f(3x) + 1, given f(x) = 2x^3 - 6x^2 + 8

 

[boredsatan]

how would you solve the inequation 9x^3 - 3x^2 - 24x - 12<0

 

[boredsatan]

Any help would be greatly appreciated

 

[boredsatan]

Anyone?

 

[InteGrand]

how would you solve the inequation 9x^3 - 3x^2 - 24x - 12<0

Any help would be greatly appreciated

Anyone?

Try and factorise the cubic.

 

[boredsatan]

Try and factorise the cubic.

3(x+1)(x-2)(3x+2)<0

 

[InteGrand]

3(x+1)(x-2)(3x+2)<0

Once you've factorised the cubic, you should be able to sketch its graph and deduce from that the solution to the inequation.

 

[boredsatan]

Once you've factorised the cubic, you should be able to sketch its graph and deduce from that the solution to the inequation.

x = -1, x = 2, x = -2/3,
is x greater than all three of these values

 

[InteGrand]

x = -1, x = 2, x = -2/3,
is x greater than all three of these values

No