boredsatan
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- 1998
y = √(-3x+5), how would you find the inverse of this equation?
Anyone?y = √(-3x+5), how would you find the inverse of this equation?
y = √(-3x+5), how would you find the inverse of this equation?
Write x in terms of y. Square both sides as the first step. And make sure to state the correct domain.Anyone?
y = 2√(x+1) - 4
what would the endpoint of this equation be?
What would the domain and range be?
How did you find the endpoint?
You can't square root a negativeHow did you find the endpoint?
so would y = 2√(x+4) - 5 have an endpoint of (-4,-5)?You can't square root a negative
If x<-1 then you square root a negative. So the endpoint is at x=-1
Also, the domain should be x≥-1 and range y≥-4, i.e. the inequalities should not be strict
Yesso would y = 2√(x+4) - 5 have an endpoint of (-4,-5)?
You can work it out for yourself in the future.so would y = 2√(x+4) - 5 have an endpoint of (-4,-5)?
how would you solve the inequation 9x^3 - 3x^2 - 24x - 12<0
Any help would be greatly appreciated
Try and factorise the cubic.Anyone?
3(x+1)(x-2)(3x+2)<0Try and factorise the cubic.
Once you've factorised the cubic, you should be able to sketch its graph and deduce from that the solution to the inequation.3(x+1)(x-2)(3x+2)<0
x = -1, x = 2, x = -2/3,Once you've factorised the cubic, you should be able to sketch its graph and deduce from that the solution to the inequation.
Nox = -1, x = 2, x = -2/3,
is x greater than all three of these values