basic algebra and arithmetic "marathon". (2 Viewers)

mirakon

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|t+2|<5-|3t-1|
t^2+4t+4<5-(9t^2-6t+1)
10t^2-2t<0
2t(5t-1)<0

therefore 0<T<1 p quote]< 5[>
doesn't look right to me....................

Don't you have to squarethe whole RHS instead of just what's in the absolute?
 

hscishard

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Ummm you both used a very difficult way. You guys didn't sqaure it right.

5-|3t-1| sqaured is this!
(5-|3t-1|) sqaured.

Better use the case method :)
 

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