Mathematics solutions (1 Viewer)

perpetuity

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Wow you don't need to be so condescending.
For the ones that were 2 or more marks, i may have got 1 or 2.
90/120 isn't that bad, is it?
it is shit. especially on such an easy paper. The papers get easier every year (I am not kidding). 2011 paper is easily the easiest 2unit hsc paper in the last 11 years.
 

jamesfirst

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guys does it matter if I didn't use millions as in literally millions.
 

cheschirecat

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Eh either way with a 90/120 that's still a high band 5 which is alright :) don't worry too much awkward_ninja
 

cheschirecat

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guys does it matter if I didn't use millions as in literally millions.
if you put your asnwer in the form 5million instead of 5,000,000 that should be fine :)
(I know the answer isn't 5 mill but that's just an example)
 

Awkward_Ninja

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it is shit. especially on such an easy paper. The papers get easier every year (I am not kidding).
Fantastic narrative mate.

Frankly, its about 10% better than my trial, and i topped my trial at maths.
You trying to say my whole class is a bunch of dumbasses?
 

taeyang

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how can you guys remember any of your answers.. I cannot even remember the questions AT all.
 

someth1ng

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I wrote my answers on the question booklet aswell as the answer booklet. Only the answer booklet has the working - obviously.
 

OmmU

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I wrote my answers on the question booklet aswell as the answer booklet. Only the answer booklet has the working - obviously.
I wish I did that in the free time I didn't have xD I would have been able to check my answers and get a rough mark.
 

Mjontrix

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for the graph question where you have to stae the region. Can i move the y value over to the other side, so it'll be less/greater than 0?
 

Tennisaddict

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My proof for 9aii)

If AB = AC, and AD = AE (given)
Then BC is parallel to DE (equal intercept theory)

RTP triangle BCF is congruent to triangle DFE
Angle BFC = DFE (vertically opposite)
Angle FBC = FED (alternate angles in parallel lines)
Therefore triangle BCF is congruent to triangle DFE (AAA)

We know BC : DE = 1 : 2,

Hence in similar triangles BCF and DFC

BC : DE = BF : FE (corresponding sides)
Therefore BF : FE = 1 : 2

Is this reasoning correct?
 

umz93

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What was the question for 6(b)iii? Also for the derivative graph, is the correct x intercept one mark/if i pointed out the st pt but drew it incorrectly?
 

Proteus

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Thanks, my answers were largely the same as yours. (Which is a good sign)

how can you guys remember any of your answers.. I cannot even remember the questions AT all.
I don't really remember them exactly, I took the test paper home and after comparing the answers with the questions, it sort of jogs the memory a bit and you have an idea whether you got it or not!
 

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