Search results

In my opinion, both B and C seem correct to me. A deterioration in the terms of trade means that more imports can be purchased for the same amount of exports, or less exports are purchased for the same amount of imports. So by going off this, you could say that there would be increased volume of...

Well from the sounds of it, I am predicting that you will either get band 6 or a high band 5, which are equally as awesome to achieve because English scales like crazy.

How about your rank?

If that's the case then, getting 13/15 is an awesome mark.

re: HSC Chemistry Marathon Archive That is quite true, breaking bonds in fact absorb energy (its an endothermic process).

Anyone else getting really nervous for the HSC?

Re: 2015 HSC Economics Marathon Well independent also asks monetary every single year, so its not really a reliable indicator.

Its obviously to prove: i = \sqrt{-1}

Re: 2015 HSC Economics Marathon Uhhh I think its worth mentioning that Fiscal and Labour market policies have been asked last year. That being said, from what I noticed, previous year essays questions end up being this years short answer.

re: HSC Chemistry Marathon Archive Ive always kept them separate

I now have a feeling that the upcoming bos trial is going to have questions based on proving principles that we simply just accepted in high school, for 4u of course.

Re: MX2 2015 Integration Marathon I was able to manipulate the question down to this integral: -2 \int_{0}^{1} \frac{\ln{\left(\frac{4x(1-x^2)}{(1+x^2)^2}\right)}}{1+x^2} dx If someone can find a way to make it equal to \frac{\pi}{2}\ln{2} then the integral can be solved

That could be said for answer B as well. As the currency for a country experiencing a boom is usually appreciated, whereas a country experiencing a recession has a depreciated currency. So the answer is identical with D then. I would of went with A for the reasons Mikes said above

Sydney Grammar. I also recommend doing Sydney Boys, and the North Sydney schools are pretty decent also.

I probably wont make an extension 2 guide. Ill leave that for leehuan and porcupinetree

Something that is worth mentioning is that Drsoccerball did like 2-3 past papers every day (Teachers in class would get pissed off at him because of how many questions he was doing during class time). So the moral of the story is that you need dedication. Dedication is key, especially when you...

How do I get a state rank?

You mean inside the log, not the denominator?

Can you please show your working out, because I don't see how else you can get: \int_{0}^{\frac{\pi}{4}} \ln{(1+\tan^{2}\theta)} d\theta to equal: \int_{0}^{\frac{\pi}{4}} \ln{(1+\tan\theta)} d\theta and get to the answer you suggested