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Re: funny HSC answers? <3

Re: funny HSC answers? Subject: Metaphors Found in NSW Year 12 English essays Her face was a perfect oval, like a circle that had its two sides gently compressed by a Thigh Master. She grew on him like she was a colony of E. coli and he was room-temperature prime English beef...

That was my reaction...

I was screwed the moment I stopped caring...

:wave:

And for that reason... I love you instead...:)

fuck, you have a point there!

Well aren't you a manly man!

<3 the crappy standards... To get to the point of having a guy lying naked on top of her is 'sexual immorality' according to her faith. Whatever way you look at it, she's in denial. D - E - N - I - A - L. and thanks olay :) I had gathered it was a Catholic concept, yes. Wow it works...

for n=1 LHS=2(1)^3 - 2(1) LHS=2 - 2 = 0??? This doesn't work: is there meant to be brackets around your '3 - 2n'??? make sure there's always brackets when there needs to be. Confirm and ill give it a shot!

There are waaaaaaaaay more attractive bags than that in shoulder strap style (enter the man bag). Just make sure you get a hot one!!!

http://www.brisinst.org.au/resources/dawson_andrea_malouf.html

I've got: Jason and The Argonauts The Elgin Marbles Thera Fakes and Forgeries Lighthouse at Alexandria Iceman Tutankhamun Any you need?

My Prelim Summary. You will also need more info on the religious aspect of it hint: Celtic. I would give you more but i gave my AH folder to a friend. Need any more summary topics I probably got em. Just make sure you double check my research: Most of these were video notes, and I think it...

bad decision. it's a no brainer but you got it wrong. go back to your own forum, junior!

Remember this result: cos2x = 1 - 2sinxsinx sinxsinx = 1/2(1-cos2x) integral sign = } i) A = } pi/2 , 0 , sinxsinx . dx = } pi/2 , 0 , 1/2(1-cos2x) . dx = 1/2 } pi/2 , 0 , (1-cos2x) . dx = 1/2 [x - 1/2sin2x] , pi/2 , 0 = 1/2 [(pi/2 - 1/2sinpi) - (0 - 1/2sin0)] = 1/2 [pi/2...

ok... =(x - (1/x))(x^2 - 2 + (1/x^2)) =x^3 - 2x + 1/x - x + 2/x - 1/x^3 =x^3 - 3x + 3x^-1 - x^-3 = - x^-3 + 3x^-1 - 3x + x^3 Ascending powers of x is just the order you arrange it in at the end.

Give us a copy and we can help (Link please...)

ii) y'= -e^x m of tan = -e y+e=-e(x-1)

uh huh!