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60-70 is what i get, (hopefully i don't make silly mistake in 1st 2 questions) you should be like 90+ atleast

your definition of passing 100+?

sometimes it is easier to find f"(x) and sub the point in, eg, if f"(x)>0 then it's min. if f"(x)<0 then it's max

that wasn't 64, it was 68 :)

can't be top mark of 64, not even bonnyrigg is that low. we bonnyrigg people got 85 as top :)

thats good for me then :) i only get like 70's so woo hoo!

sub the conjugate root in equation

some fail, but not that much, surely you can get 60/120 with no problems. i think most ppl avg between 70-80 out of 120

use quadratic 2(i+1)±sq rt (-32i) ----------------------- 2i note* sq rt -32i x²-y²=0 2xy=-32 y=-16/x x²-256/x²=0 x^4-256=0 (x²-16)(x²+16)=0 (x-4)(x+4)=0 when x = 4, y = -4 and x=-4, y = 4 so 2(i+1)±(4-4i) ---------------- 2i (3-i)/i & (-1+3i)/i rationalise 1+3i &...

a game of poker with 52 cards, find the probability of getting 4 aces.

it's always handy to know it. sin is postive in 1st and 2nd quadrant cos is postive in 1st and 4th quadrant tan is postive in 1st and 3rd quadrant each quadrant is 90 degrees

umm, how can i explain it. hmm. lets use an example. some person shoots an arrow and as a probability of 1/3 that he/she will hit the target. find the probability that in 10 shoots, he/she hits the target ATLEAST once. so normally, you would find probability of hitting exactly once, then...

ah i see, your simpsons rule question, you said part a is easy so i won't bother, basically, the area you found is the non water part of the rectangle, so the water part is area of rectangle minus area you found in 'a' area of rectangle 120x110 = 13200 area you found in part 'a' = 8350...

"In a random arrangement of the letters of the word NUMBER what is the probabilty that the two vowels will come together?" total arrangements = 6! => 720 vowels together arrangements = 5!x2! => 240 probability 360/720 => 1/3 "How many numbers divisible by 5 can be made with the digits 2...

outlier is the weird one, eg, what people got on their math test on monday, person A got 50%, person B got 45%, person C got 48%, person D got 51% and person E got 99%, person E is therefore the outlier. i don't do general maths but i'm guessing you ignore any outliers? i don't understand...

can't do ∫6e^[x^(x/2)] dx but can do ∫6e^[x^2] dx ∫6e^x² dx =6∫e^x² dx =6√[π*erfi (x√log e)]/2√[log e] =3√[π*erfi (x√log e)]/√[log e] +c (where 'c' is constant) *note erfi = imaginary error function

you don't need to write +c, it can be +a,+b, etc as long as you label "where (letter) is constant"

obviously it has to be integration. question 1 is always easiest in hsc

he factorised 5/2 out

ok ok, i said 'think', wasn't implying you were wrong