intergration gives you the area between the curve and the axis
and you obtain an negative answer whenever the area is on the negative side of the axis
you use abosulte value when they ask you for an area not then value
because you cannot have a negative area ><
well actually faradays law is like this
as a wire cuts lines of flux it wil experience a change of flux causing a seperation of charge, and thus creating an electric field, and inducing an electric field and a current should the circuit be closed.
ahh crap im an idiot >< your right they will
just imagine the backspin 'external force' from the other direction >< but still under the ball
behold my crappy drawing skills
2
the angle at the center is double that at teh circumference therefore
double angle at the center = angle at circumference
2(x-19) = 64
2x - 38 = 64
2x = 102
x = 51
3 does not involve prq or rqt
i think you are refering to question 8 where i used angle of alternate segment
9...
2
bca = 2 boa (angle at circumference is half angle at center)
64 = 2(x - 19)
102 = 2x
x = 51
3 prove congurent trianges OAC & OBC (SAS)
then from that
2x - 15 = 140
2x = 155
x = 77.5
8
2x + 17 = x + 31
x = 14
9
as tangents are always perependicular to the center
90 - ((180 - 96)/2) = x...
YAY same we only up to complex numbers as well ... although we have reached representation through vectors which isnt hard if you do physics and engineering ><
backspin is when a force is applied to cause the ball to spin backwards
topspin is the opposite
here s a diagram i made
it really helps it you play something like tabletennis, tennis or cricket ^^
refer to the diagram
the angle a & b are equal because they both subtend the same are zw
subtend means to go from a pt to some place basically i could explain it more if you wanted
are you sure your talking bout the right thing? i think he means circular motion in general
basically you know how the linear velocity is always tangential right?
well if you take 2 points on the circle and then find dv using vector 'subtraction'
as
a = v - u
t
disconerning time the...
hmm so i guess my part one was slightly wrong ... im still getting used to the [ sub ] >< it tends to clog it up a lil
thanks for checking rivet ^^
well second derivative is used to find which way the curve is turning so if the curve is turning upwards then it must have a minimum
so basically...
1) Find all stationary points and inflexions on the curve y=(2x+1)(x-2)4
y' = u'v + v'u
u = 2x + 1
v = (x-2)4
then
y' = 2(x-2)4 + 4(2x + 1)(x-2)3
= 2(x-2)3 { (x - 2) + 2(2x + 1) }
= 2(x-2)3 { 5x }
when y' = 0 then there is a turning pt
therefore
case one
x-2 = 0
x =...