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kinetic energy changes to heat (work done by friction) (1/2)mv^2 = umgs where u is coeff of kinetic friction, s displacement (1/2)(15)^2 = u(9.8)(25) etc

This is not in the table. Sorry.

You look up the table of indefinite integrals and then work out definite integral (0 to x).

Irrational numbers are real numbers. Since root(-6) is a complex number, .: it is not an irrational number.

ignore 'not required by the question'

I think you confused y=(3x+1)^2 with y=[3(x+1)]^2. The latter represents horizontal dilation of y=x^2 by a factor of 1/3. y=(x+1)^2 is the translation of y=x^2 to the left by 1 unit and y=[3(x+1)]^2 is the translation of y=3x^2 to the left by the same amount. So dilation does not affect...

Let the angle of launch be @. Vertical component: u = +100sin@, v = -100sin@, a = -9.8, .: t = 20.41sin@. Horizontal component: u = +100cos@, t = 20.41sin@, s = +500.0 .: +500.0 = +100co@ x 20.41sin@ 0.49 = 2sin@ cos@ = sin2@ @ =14.97 degrees

(tanx)^5 = (tanx)^3 (tanx)^2 =(tanx)^3 ((secx)^2 - 1) = (tanx)^3 (secx)^2 - (tanx)^3 integ[(tanx)^5]dx = integ[(tanx)^3 (secx)^2]dx - integ[(tanx)^3]dx etc.

(1) <SUP>n+1 </SUP>P<SUB>2 </SUB>= 4n +10, (n + 1)n = 4n + 10, n^2 + n = 4n + 10, n^2 - 3n - 10 = 0, (n - 5)(n + 2) = 0, .: n = 5 (2) (0 + 1 + 2 + 3)(0 + 1 + 2 + 3 + 4 + 5 + 6) = 6 x 21 = 126

Choice a. The one thrown upward has the same speed downward when it passes through the point of projection.

1. Not A. Which one of B, C, D and E depends on the mass of the ball and air resistance. 2. A 3. A 4. B 5. A

du = (2x+x2)ex dx when u = x2ex

Use the gradient of PN, OP and y = x to show anglePON = anglePNO.

haque's way is simpler

General, Mathematics, Ext1, Ext2 exam solutions 2005, 2006 http://www.itute.com/mathline/exams_solutions.html

a stays as a, b stays as b.