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Questions 3-6 Like before, possibility of errors. Let me know if you find any and ill fix it edit: fixed up q3(a)

omg i saw waf yesterday!

I trust FF got q1 and 2 right so ill do some. Ill start from the end as thats the ones most people want. 10(a) (i) dv/dt = k so dv = k dt for some constant k. Integrating both sides gives v = kt + c1 (ii) Integrate v = kt + c1 to get x. x = 1/2(kt2) + c1t + c2 When t = 0, x = 1 so 1 = 0...

http://www.hsccoaching.com/Downloads.html Chapter 21 has what you seek :)

haha snapperhead, do you recall this:

azzikiel, I'd be very careful about what I say, whether jokingly or not. The seriousness of such an act is something many students do not seem to understand. I personally know the results of such events and was indirectly involved, although not for the CSSA trial. As for some tips, I sat the...

Doesnt say anything in the handbook

Im not entirely convinced, although the possibilities do look good, the prospective employment in this area is the greatest factor contributing to my lack of enthusiasm for such a field. I mean what chances do I have of getting on a fleet such as this one, especially straight out of tertiary...

Before I decided 4 unit was a no go for me, we were doing 1 hour/week. Mixing that with no homework for it whatsoever == very bad marks for topic test :)

Theres your problem, by dividing both sides by x you are eliminating a solution. Instead, factorise: 0=12x-3x2 3x(4-x) = 0 x = 0 or 4 y"=12-6x At x = 0, y'' = 12 > 0 so theres a min at x = 0

Id be willing to write up solutions if someone uploads the actual exam

4a2 -10ab+10b2 + K(3a2 -10ab+3b2 ) = (4+3k)a2 - (10+10k)ab + (10+3k)b2 Recall how you expand a perfect square (ka - mb)2 (where k and m are any numbers): (ka - mb)2 = k2a2 - 2kmab + m2b2 the coefficient of ab = -2km = -2*root(coefficient of a2)*root(coefficient of b2) So in the...

Do you mean 4x + 3y - 6 = 0?

Captain Slide does it again :p

Nothing wrong with it, I like to use that method especially for double variable differentiation.

If i remember my informatics lectures right, then slide rules were used for logs and raising something to a power can easily be done with the use of logs.

I thought involution was about raising things to powers

Quadratic function & coordinate geometry

My laptop (connected wirelessly) usually hits ~12Mbps, my PC (wired) usually hits about 15+. And yes, yesterday was annoying, couldnt have happened at a worse time for me.

One way you could do it, which may be sufficient for 2 unit, is to plot y = sinx and y = tan(x/2) and notice that the only place they meet is at 0, pi and 2pi. Not very elegant though