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(1+w+3w^2)^2 = (1+w+w^2 + 2w^2)^2 = (0 + 2w^2)^2 = 4w^4

to find asy, take the limit as x -> infinity and -infinity try to get something of the form 1/x since as x-> infinity, 1/x = 0 and so it disappears and you've made the expression simpler in this Q, divide both sides by x^3

since I'm here I might as well answer ur Q.. (note: when I started typing aural hadnt replied) 7. unity = 1 (also if u see the term "unit circle" later, it means circle of radius one, centred at origin) cube root is.. the third root... w is the cube root of 1 so w^3 = 1 let z^3 = 1 and...

I believe it's not possible to identify whether tywebb and buchanan are using the same machine. It's possible to show that the two machines are currently having the same IP address at the time of detection but that is not enough to conclude that the two machines are the same machine. It is...

who says complex number is the easiest topic :p I hate those which involve some geometrical interpretation polynomial should be the easiest IMO (note: this excludes HSC Q8(b) polynomial :p :p) Actually polynomial questions in the HSC are harder than the complex number questions. But in...

LOL it's a who.. as to who he is, I'll let someone else answer that coz I dont really know him myself

that Q is more popular than I thought LOL if only Laurie Field reads this he'll start debating again EDIT: gosh he does well in every single subject.. http://www.boredofstudies.org/community/showthread.php?p=1042889#post1042889

McLake, those two files are essentially identical... I downloaded them out of curiosity :p and I guess it's a good idea to make separate files for 2U, ext1 and ext2...

give me a Q which is off the syllabus (just curious...)

or use the one by Mr Hansen and Mr Haggar http://www.boredofstudies.org/community/showthread.php?t=49562 its also in the resources section it has an error unfortunately which is pointed out in the linked thread

oh by the way, how does this belong to "Trignometric inequations" ;)

or u can do some sort of inspection from the quad formula u have sin(x)=0.700948797 OR -0.880948797 for 0 < x < 2pi, x = 0.7767, 2.3649, 4.219, 5.2053 (assuming there is no human error) you want 16cosx=3+12sinx just substitute the four x values using this machine called calculator...

failure of the quadratic... Fields medal :p by inspection, :D

actually T(n)= T(n-1) + T(n-2) + T(n-3) for all integers n>=1 if you define the following: T(-1) = -1 T(-2) = 1 T(-3) = 1 :p I know I'm not helping haha... btw for less enthusiastic maths students, this sort of questions is very unlikely to be asked in hsc exams. the syllabus only...

LOL.. its really easy to make a new thread since they "bisect" at 90 degrees (actually they dont bisect since z1-z2 has its tail at the origin), arg (z1 + z2)/(z1 - z2) = 90 (or -90) because arg x/y = arg x - arg y (z1 + z2)/(z1 - z2) = r cis(+- 90) cos (+-90) = 0 so the real part...

oh, forgot to mention that I dont think past papers are suitable for preparation for assessments before trial and for study at an early stage of your year 12. reading the textbook (not just the exercises but also the paragraphs) is a good idea to understand concepts.

u know how many ext2 papers I've done in my life? seven! (or maybe eight): hsc 1998, 2000-2003 and the rest are some trials a bit more if u count school assessments as papers and seven for ext1 too lol never got to do all those damn papers but I didnt do too well in the exam :p u hav...

u need a bit more effort to get what you want God I cant even think what effort you need :P ok becoz Im really nice tonight, ill give u the direct link: http://nsweduserv.freeserverhost.com/maths/mathspapers.html then click on nsweducationalservice for the papers I provide if u want those...

I deleted it go to the "Good Maths Website" thread and go to the last post (well atm its the last post) deleted it becoz it has polls EDIT: actually, just click on the link on my signature

do u think some of these stores will have further discounts for christmas or new year? is it better to wait?