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10) i) for this q differentiate y, then let itequal 2, since the line is parallel to the tangent, they have the same gradient. That will get you the x-coordinate of the point of contact sub it back into the original eq to get the y coord. ii)basically do the same as in i) but when you let the...

let u=arcsinx and v'=x work from there as x is easier to integrate then arcsinx i.e. use Iv'u.dx =uv-Ivu'.dx

Unless his school does the topics in a different order, or he studyed ahead...

I'd say keep it as it makes 2unit seem so much easier, as you're provided with a range of more difficult questions, in extension 1.

I think 95% was the highest in our last test. and then most of the "top" people got around 80-90 and so on...

Cointerior angles. If you want to be precise you could label the parallelogram and say something like: a=180-53 (cointerior angles, AB//BC)

I worked out an extremely long 4 unit, definite integral all the way to the correct answer,when typing it in to the calculator i got the correct answer it was something like 130. However, i wrote 131....>.> lost a mark lol.

For the first one, let x=asin@ or acos@, your choice really. For the second one, try t-formulae i suppose. T-formulae for the third aswell, or try manipulating using trig.

Complex Numbers, Curve Sketching, Integration, Polynomials and almost finished harder three unit.

Nope, If you choose extension 2 and sit for the hsc exam, they disregard your 2 unit mark. Extension 1 and extension 2 each count for 2 units.

Ranking in your grade.

I(cosecx)^2 =I(sec(n/2-x))^2, using complimentary angles =-I-(sec(n/2-x))^2 =-tan(n/2-x)+C =-cotx+C

I was under the impression that acids don't dissociate the ionise?, so doesn't it actually form 2 hydronium ions?

I(secx)^3(tanx).dx I(cosecx).dx I(secx)^2.dx Could someone please help me with these three questions, thanks

Nah, English fundamentals is some random 1 unit english course that only people in ESL or standard can do.

calculate, how far an astronaut would need to be away above the Earth in order for his weight to be 0.01 his weigth on the Earth's surface?

Wouldn't it just be something like, the gravitational field will be in the direction of the centre of the largest mass( the massive object) and the effect on other masses is that it pulls them towards its centre due to the gravitational force of attraction experienced between masses.

You calculate how many moles is required per litre, say 2, by using n=cv then since you already have it in J/mol- you multiply it by 2 to get it in litres or however many moles one litre is.

H₃C₆H₅O_{7+H2O--> H30+ +}C₆H7O_{7 C6H707+H20---> C6H6O7 2- + H30+ C6h6O7 + H20 ---> C6H5O7 +H30+ Same process for the other one but, it onle inoises twice, as it is diprotic.}

Oops :read: