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    Official BOS Study Meat v2.0 (Winter Edition)

    would L'Hopital's Rule be included? maybe it's too time consuming
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 it seems #1 is updated I believe Drongoski's talk about limits is gonna be rather interesting
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 most kebab shops ? we should really stay on topic pizza sounds like a good idea PS @Ozko, is this the one you're talking about:
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 meet box FTW this is why you guys should come to Usyd (jks, eating a meatbox is actually quite time-consuming, not very neat either, regardless of its health effects besides, I'm not even going ) from what I read in the library's website, there'd be...
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 I'm plagiarising your latex code: \forall \forall, \exists \exists PS: mathematicians are not very good at making jokes
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 as far as I can see, there are quite a few people helping with maths so I'd guess we may need more tutors in other subjects
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 http://www.parracity.nsw.gov.au/play/facilities/library/about_library/facilities#lib_meet are these 3 meeting rooms the ones you're talking about?
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    Rectangular hyperbola 1999 CSSA

    since x=3/2 is a double root, then P(3/2)= (3/2)^4-2(3/2)^3+c^4=0 ,we'd get c^4=27/16 [I expanded everything, P(x)=x^4-2x^3+c^4] then P(x)=x^4-2x^3+27/16 has a double root x=3/2 let the other 2 roots be a and b a+b+3/2+3/2=2 ==> a+b=-1 ab(3/2)*(3/2)=27/16 ==> ab=3/4 so a...
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    Rectangular hyperbola 1999 CSSA

    thanks for reminding me it doesn't always have to be a double root, but the multiplicity must be even for example, f(x)=x^4 but in this case, it just happens to be a double root (since quadruple root doesn't work, and it's a quartic)
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    Rectangular hyperbola 1999 CSSA

    but I think you'll need to justify why it's only a double root not triple, or quadruple [find P'(x) , P''(x), P'''(x) ] PS: it could only be either double or quadruple, since they're touching
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    Rectangular hyperbola 1999 CSSA

    the black one is the actual graph if it's a single root(red curve), then it must intersect y=0 again, giving us another real solution, condradicting the fact that there's only 1 point where they touch
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    Rectangular hyperbola 1999 CSSA

    solve simlutaneouly , as suggested by 4025808 you'd obtain the quartic in the question circle TOUCHES hyperbola implies that there is a real solution that's a DOUBLE root EDIT: it's doesn't , see #11 then from your graph, you can see that point must the be ONLY place where they...
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    Rectangular hyperbola 1999 CSSA

    is it just me , or you can't really see the question clearly?
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    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) what I picture in my mind when I see the word 'ladder' when was the last time you've seen one of these: I guess one could make a somewhat a variation of the question, using the 1st one
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    HSC 2012 MX1 Marathon #2 (archive)

    Re: HSC 2012 Marathon :) maths teachers NEED better ladders
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    Limits in uploads

    try http://www.mediafire.com/ or something similar
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    Official BOS Study Meat v2.0 (Winter Edition)

    Re: Official BOS Study Meat v2.0 travelling overseas during the Winter Holiday for university students (which coincides with the upcoming school holiday) So I guess I'll probably join you guys next time and thanks for Carrotsticks organising this event
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    is there any double angles or stuff such as sin(x+y)=sinxcosy+cosxsiny in the 2u hsc

    Re: is there any double angles or stuff such as sin(x+y)=sinxcosy+cosxsiny in the 2u http://www.boardofstudies.nsw.edu.au/syllabus_hsc/pdf_doc/maths23u_syl.pdf P40
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    MX1 to MX2 Difficulty?

    obviously, MX2 is quite different from MX1 in terms of both course content and the difficulty of exam questions one might argue that you may end up with a higher scaled mark(thus ATAR as well) in the end even though you might not be as confident in your understanding of the subject And I...
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    MX1 to MX2 Difficulty?

    http://www.uac.edu.au/documents/atar/2011_HSC_Table%20A3.pdf
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