Search results

Can I conclude that -4k >=0 - for example

Can I conclude that a negative answer is >= 0. I know that obviously you cannot for > only but since there is 'EQUAL TO' can I assume that?

yeah but like when studying for tests in yr 11 that dont really have past papers like mod1-2 what do u do

So during exam times in yr 11 what did u use to study if u barely used the textbooks

then what did you use

^

ok thks

^

^

Hi can anyone tell me what the best textbooks are for chemistry and physics since there is a wide variety of different ones and especially those who band 6-ed what the main textbook for sciences was for them? which ones are the best

ok

2. Prove by mathematical induction that 3^n > 1+2n for all integers n>/2 For n=2 LHS= 9 RHS=1+2(2)=5 Thus LHS>RHS True Assume n=k 3^k >1+2k RTP; n=k+1 3^k+1 > 1+2(k+1) 3^k+1> 2k+3 LHS= 3(1+2k) = 3+6k (using assumption) >2k+3 Thus, 3^k+1>2k+3 Therefore true for n=1, k, k+1 Thus...

thankks yes because its meant to be n>/1

I kinda get it now thx

thank u so much

1. Using Mathematical induction, prove that n^2 + 1 > n for all integers n>1 For n=1 LHS= (2)^2+1= 5 RHS=2 Thus LHS>RHS, therefore true Assume n=k, k^2+1 >K RTP; n=k+1 (k+1)^2 +1 > k+1 Now what do I do and how do I go about it

Have already spent hours trynna find yt vids and stuff to help me out but im so lost pls help

1. Using Mathematical induction, prove that n^2 + 1 > n for all integers n>1 For n=1 LHS= (2)^2+1= 5 RHS=2 Thus LHS>RHS, therefore true Assume n=k, k^2+1 >K RTP; n=k+1 (k+1)^2 +1 > k+1 Now what do I do and how do I go about it

No Im missing the rest I can easily say Let n=k and n=K+1 for the given expression but I cant do the rest

My main problem is how to go about the question after letting n=k and n=k+1