MedVision ad

Search results

  1. J

    Cramming success stories?

    ^ yup can confirm, and he achieved some pree great marks OP, unfortunate you have 2 exams, but u got this mate!
  2. J

    Eng. Advanced

    Well that sucks
  3. J

    Australian Maths Competition

    Re: Westpac Maths Comp marathon Refer to the previous posts
  4. J

    2017ers Chit-Chat Thread

    i guessed like 100% of it lol
  5. J

    Australian Maths Competition

    http://imgur.com/a/uDxq1 you found the diameter of a circle with area 16pi, not the diameter of the tube
  6. J

    Fave 3U topic??

    circle geo cause its fun
  7. J

    Looking for Maths tutoring mathematics 2 unit

    well you gotta look for someone who can actually teach m8, not someone who just gets 100s ;)
  8. J

    Actuarial + Engineering

    relax we get it mate
  9. J

    Help with Derivative question

    Hey! Thanks for pointing that out :) I did keep it as exact as possible till the very end indeed (as seen by the ellipses if you are talking about the line with the fractions) :)
  10. J

    Help with Derivative question

    $\noindent$ \mathbf{(a)}$ When $x=1.01, y=(1.01)^4+1 = 2.040604... \\ $ Gradient $=\frac{y_2-y_1}{x_2-x1} = \frac{2.0406.. - 2}{1.01-1} = 4.0604 \\ \\\mathbf{(b)}$ Repeating the process again, we get 3.994
  11. J

    HSC Physics Marathon 2017

    LOL THIS QUESTION! hahah
  12. J

    what's your fave ice-cream?

    thats golden bruh
  13. J

    SHM Question

    The acceleration is always 0 when x=centre of motion (cause a=-n^2(x-b)) . If x was the least at x=0, then the centre of motion would be somewhere above 0 (and acceleration would be 0 at that point)
  14. J

    HSC 2017-2019 MX2 Marathon ADVANCED

    Re: HSC 2017 MX2 Marathon ADVANCED $ \noindent $ \cos \frac{\pi}{4}=\frac{\sqrt{2}}{2} \\ \\ 2 \cos^2 \frac{\pi}{8}-1=\frac{\sqrt{2}}{2} \\ \\ \Rightarrow \cos \frac{\pi}{8}=\frac{1}{2}\sqrt{2+\sqrt{2}} \\ \\$ Similarly, $ \sin \frac{\pi}{8}=\frac{1}{2}\sqrt{2-\sqrt{2}} \\ \\ \therefore 3...
  15. J

    HSC 2017 MX2 Marathon (archive)

    Re: HSC 2017 MX2 Marathon $ \noindent Given $ S_n =\sum_{k=1}^{n}k^2. $ Prove by mathematical induction that: $\\ \\ \qquad nS_{n}-\sum_{r=1}^{n-1}S_r= \sum_{r=1}^{n}r^3 \quad \forall n\in \mathbb{Z}: n>1
  16. J

    permutations

    lol here's an (another!) alternate way Case 1: Each team has 1 person it in. So the first team has person A and the other team has person B. We need to choose 3 people in the first from 7. So 7C3. For the other team, we need to choose 3 people from 4. So 4C3. So total = 4C3*7C3*1C1 = 140. We...
  17. J

    Chemistry Option Topics

    The school chooses the option for you. You can, however, learn an option topic by yourself but I do not think that is a good idea
Top