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Tutoring is for bums :p (99.35) though to be fair I had some excellent teachers.

Killer marks dude, you gotta be in the running for dux with that.

You've been trawling through results making cruel comments despite having already done this stuff last year - move on and get a life. (edit: pwned, see below)

I can definately be happy with this one - UAI: 99.35 Marks: (for future SAMs and all that) Chemistry - 90 English adv- 88 English ext 1 - 45 Math ext 1 - 97 Math ext 2 - 95 Physics - 93

Chemistry - 90 English adv- 88 English ext 1 - 45 Math ext 1 - 97 Math ext 2 - 95 Physics - 93 I'm a tad dissapointed about english advanced even though it's quite a fair reflection of the amount of work I put in. UAI thingies would suggest something in the range of 98.6 - 99.3 which I...

Thanks for the shoutout - I'm counting on you to make my internal chem mark awesome ;) (a feat I'm sure you will have managed). [p.s. airness will kill the humanities]

I'll vote for aural_sax05, that is, if his confidence is anything to go by ;-). (Edit: and wholovesmaths, without a doubt)

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For this one it's probably best to combine the brackets a bit to get: (y² - 1/y²)⁷(y + 1/y)³ = (y² - 1/y²)⁷(y³ + 3y + 3/y + y^-3) In the left bracket the first power in the expansion is...

A line through (3,0) and (4,10) is rotated around the y-axis between y=0 and y=5

Hey! The Who make for awesome credit music :p.

expressing z = 1 + √3i in mod-arg form gives us 2.cis(π/3) so, zⁿ = 2ⁿcis(nπ/3) zⁿ is real when Im(zⁿ) = 0 , that is, when Im(zⁿ) = 2ⁿsin(nπ/3) which is equal to zero when nπ/3 = kπ ----> n=3k where k =...

I love that internal assessment rankings count for a decent amount 'cause mine are going to save my ass where I did dumb shit in the exams - e.g. 3 - 1 = 4 (yes I did this... and it will have cost me 2 marks in ext 1 :D) Course Name Units Rank Order Outside School 15050 Chemistry 2 3 /...

It might be helpful to start with some of the mod/arg properties e.g. |zw| = |z|.|w| and arg(zw) = arg(z) + arg(w) so for the first one you have: a) |(1-i)z²| = |(1-i)|.|z²| = (√2)r² ^since |(1 - i)| is √2 and |z| = r --> |z²| =...

I would do it by considering f(x) = (x+3)/(x-2) = 1 + 5/(x - 2) This curve has a horizontal asymptote at y = 1 and a vertical one at x = 2 as well as a zero at x = -3. All you really need to know is where f(x) is ≤ 0. Using simple graph drawing or otherwise you can determine that f(x) &le...

Well we define i such that: i² = -1 or, alternatively, i = √(-1) ... that's about it really. Takes you into the complex number system.

This isn't the most straight forward way to do it but what you've got is the same form as those t substitution things so if you let R = tan(@/2) then x = cos@ and y = sin@ ∴ x2 + y2 = 1. More a cool pattern than a method to use.

Templar basically said most of the extended comments I would have liked to make regarding the USyd combined med program. However, I feel I should say (to WLM) that given your issues with others calling you 'wrong' it's a tad arrogrant to say that I am ["your statement quoted below is also...

Figuratively speaking Newton was in the driver's seat 'cause the motion of the shuttle/rocket thingo was due to newton's laws and his eq'ns of gravity. It was more like an english task - explaining the function of figurative speech in language and how the Newton reference made sense contextually.

But around a wire it's circular so it doesn't travel in a single direction.