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Nah, to paraphrase, condense and rewrite what slide rule has already said: "You fully don't."

I'll tell you after tomorow morning.

let u=sinx du=cosxdx ∫√(sinx)cos³xdx =∫√(u)(1-u²)du =∫ u^1/2 - u^5/2du =2/3 sin^3/2x - 2/7sin^7/2x +c Why does my font keep going small???...ahh, fixed it.

18. ∫secⁿx dx = ∫sec^n-2xsec²x dx so, using int. by parts where u = sec^n-2x and v'=sec²x hence v= tanx u = sec^n-2x = (cosx)^2-n u' = (n-2)sec^n-1xsinx (I can go over this bit of...

Bludger... :P. This was like a free weekend for that assignment.

Funky double negative.

How postmodern.

They better have all been pentasyllabic.

It seems as though The Board has developed an evil image. They're so secretive.

With a bit of geometry you can work out that the component of the gravity acting on the object down the hill is gsin(20)= 3.35ms^-2 Since you know the acceleration will be constant (no friction) you can use v²=u² +2as [where u=0] v= √(2as)...

17, remaining 17. Schoolies will be fun....

Don't practice. Play! "Practice" makes it sound like such a chore :P.

I've done 4 exams with 2 left to go. English had an easy question which was good considering how little I had prepared for it. Physics had a lot more science in it than I had expected, I faired pretty average on that test. The Chemistry exam was too easy, finished with 20 mins to spare (out of...

Music and a whole lot of disorder.

Nicholson St Public School (yr6 1999)

I tend to think of eddy currents as a circular current that forms in a conducter (eg. a plate of copper) to oppose change in magnetic flux. Both of those generators have an induced current according to lenz's law but I believe an eddy current is more specifically one formed in a conducting...

Jim's way is probably much quicker but if you don't have that hit of innovation then you can just use the factor theorem to find factors. P(x)= x⁵-9x³-8x²+72 P(2)= 0 P(3)= 0 P(x)= (x-2)(x-3)(x³ +5x² +10x +12) and so on...

I can understand going to a university/college which specialises in your research interests or if it has a particularly good program for something. But it just often seems to me it is, like you said, about the romantic hollywood notions. The credentials sound good but they also make you sound...

Yes, yes I do :P I'll just change that, well spotted.

HCl + NaOH -----> H₂O + NaCl i.e H⁺ + Cl^- + Na⁺ + OH^- ---> H₂O + Cl^- + Na⁺ You'll notice that an H⁺ ion is being transfered which combines with the OH^- creating that...