It wasn't a waste of time reading that. There is also the possibiliy of switching classes to get another, better teacher, if that is possible. Otherwise do what bringbackshred said.
Fourth question, the sum is of the abscissa and the ordinate, which would be the x value of the abscissa, I think that's how they got their sum, wouldn't have a clue. From there, differentiatie, then find x and y co-ordinates of point P.
Well y2 + 4y +52 = 16x
y2 + 4y + 4 = 16x - 48
(y+2)2 = 16(x-3)
(y+2)2/16 = x-3
(y+2)2/16 + 3 = x
dx/dy = (y+2)/8
dy/dx = 8/(y+2)
That's the derivative. The second bit is that this parabola is of the form x = (y-k)2, so it is a parabola that for every x-value in its domain, it has two...
:shy: She replied :embarassed:BAHAHAHAHAHAHAHAHAHA!!!!! I dare anyone to misinterpret the white text ;)
Hehe, I wouldn't mind if we didn't have the other stuff, just the late sign-in and early sign-out privileges I'd like, then more sleep for me :D which I desperately need ;)
Not really. Just means that your assessment mark will now be your HSC exam mark, regardless of how well you go, so it's in your best interests to do well in the course.