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honesty? one of my teachers was one of the people who wrote one of the CSSA trials which we sat and we didnt find out until we were sitting in the exam room and looked at the back page. They also have to sign confidentiality agreements and stuff. In the end nothing can stop this, but...

shady if u get them, could u megauplaod them for the others?

+1 true, our GPA system IS flawed, its too easy at the top end, and too harsh on the bottom end i believe.

you can view your exam script if you want, that might help you out...

yeh, congrats to all who are graduating!

congrats to all!! damn, like one of my mates - D's and HD's, but one 74.

thx, like i said,. try closing all browsers then opening one again and going to https://student1.mq.edu.au/t1tbmain.asp. worked for me straight away after 15 mins like u guys.

4HD's , all in 90's yay! a tip for ppl trying to access: i was waiting like u guys but i closed all my IE browsers then opened one again, and went to the site and it works fine

Re: Results Discusssion - Results so far and predictions also should we try https://student1.mq.edu.au/t1tbmain.asp - which doesnt load, or https://student1.mq.edu.au/ - which gives it as full?

Re: Results Discusssion - Results so far and predictions seriously, one of my mates has been logging in and out fine for 5 mins, like 5 times, but i cant even get the login page?

Re: Results Discusssion - Results so far and predictions get ur results and get off estudent so we can log in..please

Re: Results Discusssion - Results so far and predictions page not working 4 me damn, should have logged in and stayed logged in when i had the chance! does estudent only take a certain number of people or something?

Re: Results Discusssion - Results so far and predictions great - estudent: "Due to excessive load eStudent is currently unavailable. Please try eStudent again later"

i think so, because consider 7^(k)=(9Q+1)/(3k+1) let k = n+1 thus 7^(n+1)=(9Q+1)/(3(n+1)+1)=7^(n+1)=(9Q+1)/(3n+4) just swap n bak to k - theya re both dummy variables if you dont like it, just change 7^(k+1) into 7.7^k, and sub in the statement for 7^k bak in, and youll just...

i too shall skip a few steps assume n=k is true, ie assumes (3k+1)7^k-1=9Q, Q a positive integer k+1 statement is: (3(k+1)+1)7^(k+1)-1 =(7)(7^k)(3k+3+1)-1 =(7)(7^k)(3k+4)-1 =(7)(7^k)((3k+1)+3)-1 =(7)(7^k)(3k+1)+(7)(7^k)(3)-1 =(7)[(7^k)(3k+1)-1]+7+(7)(7^k)(3)-1...

great upload

Re: Results Discusssion - Results so far and predictions 12 hours to go

NEAP past papers are awesome, especially in chem and physics, mainly because of how detailed their suggested solutions are. They even give a sentence or 2 on each multiple choice. They are a great source of clarification on content relating to specific questions, such as 'evaluate' questions.

this doesnt really belong under HSC physics

definitely 2-hexene, as long as what youve drawn is correct because you name according to the longest carbon chain there's no such thing as 1-Methyl-3-Pentene is there? 3-Methyl-1-Pentene, yes, but a quick google serch supports my claim i dont know how you would go about this but that...