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Re: 2012 HSC MX2 Marathon <a href="http://www.codecogs.com/eqnedit.php?latex=\\\textrm{Let}~z_1=1@plus;2i~\textrm{and}~z_2=3@plus;i\\ \arg z_1=\frac{2}{1}=2\\ \arg z_2=\frac{1}{3}\\ ~\\\textrm{Now,}\\ \frac{z_1}{z_2} =\frac{(1@plus;2i)(3-i)}{(3@plus;i)(3-i))}=\frac{5@plus;5i}{10}\\~\\...

Year 7 & 11/12 Physics: Really awesome guy and my favourite teacher. Regularly taught us interesting stuff that's outside the syllabus (He was going to do a whole week on the standard model, but sadly stopped after 2 lessons because 90% of the class didn't understand/care), but he gets really...

I can fully understand that, but surely they could be more forthcoming with information. It's even more vague at UNSW, it just says you might need "to achievee an ATAR exceeding the mid-90's". Credit average is 65%, right?

Hmmm okay. That's what it says on the USYD website as well, but the way it phrases it makes it sound like it's not set in stone, so to speak. Thanks anyway!

Just out of curiosity, what were your marks/ATAR? I'm hoping to get in next year and everything I've read about the entry requirements is really vague.

I wouldn't say it'd be hard... but it won't be easy. I did barely any study for chem except for trials and externals (something I thoroughly regret), but still managed to pull an 86. Just put in solid and consistent effort throughout the year and you'll be fine.

Depends on how straightforward the questions are. If it's something like "what's (3+2i)(1-i)" it'll be fairly easy, but if it's something that requires working out (for example previous question 1's) there's a chance you'll make a minor mistake in your working and get 0, rather than losing a...

1- Your HSC marks. 2- Depends on your school, but I'm pretty sure there's a maximum of 5 internal assessments per subject. 3- Nope. 4- Yep. If I recall correctly in MX2 90-100/120 got you a ~95 and 110+ got 99. For MX1 it was something like 60/84 got you 95 and 80 got a 99, but this is...

This holidays I've been going to bed at around 12 and not actually falling asleep till 1 (going to try and change this soon) and during school I aim to get to bed by 10, but no later than 11, no matter what.

I'd recommend excel physics. It's not that good to actually learn from but I found it really beneficial when it came to revising for yearlies - I just read through the entire thing once or twice and it just jogged my memory and made it easy to work out the areas I had to improve in.

To be honest, I didn't have an indepth understanding of chem - something I really regret, because if I'd applied myself more I could've got 90+ easily. For physics & maths I watched lots of lectures/videos online, mainly from khanacademy (http://www.khanacademy.org/) and MIT open courseware...

The main ones are Physics, Chem and Economics alongside the classical languages (Greek, Latin etc.) from what I've heard.

Which is a rather sad state of affairs when you think about it.

My understanding is that proper time/length/mass is the time/length/mass measured by an object in its own F.O.R. (the pronumerals with the nought subscript in the three equations), so I'm a tad puzzled as well, but maybe the it's trying to say that there's not a "proper" time in the sense that...

I'm typing mine. - Leaves me room to make changes - Easy to send to teachers/friends to check it's all correct - Can't lose them - Multiple copies: I can make more cash when I sell them at the end of the year - Looks more professional (especially in latex): again, more $$

Re: 2012 HSC MX2 Marathon Shit. My school's only finished complex numbers. EDIT: Although, we've finished a fair amount of 2/3 unit (induction, series, locus, probability, perms & combs, geometry of the derivative, circle geo, binomials)

Q1. |z_1+z_2| \leq |z_1|+|z_2| Q2. |z_1+z_2+...+z_n| \leq |z_1|+|z_2|+...+|z_n| Judging from the thread title I think that's what you mean? Q1 - Consider the triangle formed by the origin, Z1 and Z1+Z2. We know that in any triangle the sum of any two side lengths is greater than the length of...

This.

http://latex.codecogs.com/gif.latex?~\\\angle&space;BDA=\angle&space;ABC=90^o&space;~\textrm{%28given%29}\\&space;\angle&space;BAD&space;=&space;\angle&space;BAC~\textrm{%28common%29}\\&space;\therefore&space;\triangle&space;ABC~|||~\triangle&space;ADB~\textrm{%28equiangular%29}\\&space;~\\&space...

http://www.youtube.com/watch?v=mhlc7peGlGg I've found this is a pretty good explanation, although the first 2 and a half minutes is just explaining the premise of the problem.