2026 HSC CHAT (5 Viewers)

WeiWeiMan

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I WANNA DO EXT 2 MATH BC MATH JUST COMES SO NATURALLY TO ME I LOVE IT
Everyone is saying not to judge too early bc yr 10 math is always always the easiest junior math n yr 11 math is gonna humble me idk tho but im aiming for ext 2 bc i love math so much
erm i didn't even ask you 🤓
jokes
ngl if you're doing well in yr10 5.3 and find it that easy, yr11 should be chill for you
if you're naturally good at math and genuinely love it, I reckon you should do ext 2.
 

jane1820

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erm i didn't even ask you 🤓
jokes
ngl if you're doing well in yr10 5.3 and find it that easy, yr11 should be chill for you
if you're naturally good at math and genuinely love it, I reckon you should do ext 2.
Yh i havent gotten below 90% so far in 5.3 except the last exam but thats bc i didnt have enough time (BRO WHEN I GOT THE TEST BACK N I REREAD THE TEST I COULDVE GOTTEN EASY 95% istg if i just had extra 10 min 😔)
fingers crossed bc everyone in yr 11 ext math is STRUGGLING like i think only 4/14 ppl passed w only one 90% which is an accelerated student im not so sure but if i do do good in ext 1 im definitely doing ext 2
 

jane1820

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When is a responsible time to start studying for yearly exams- Holidays just started but I don't wanna leave things to the last minute. 😭
My yearlies r in week 3 n i hvae left ALL MY STUDIES IN MY LOCKER except science n math n im so annoyed bc HOW TF DID I FORGET
im gonna start studying now for math n science so i can revise later n use some online resources to study for the rest of my subjects considering i dont physically have them UGH
 

isho-3

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Can anyone do this question (5.a.) for me? (Using the sine rule for finding angles)
View attachment 44383
sina/8 = sin42/6
a = sin^-1(8sin42/6)
a = 63.14...
theta = 180 - 42 - 63 = 75

yeah, it's 75 degrees. for this question, don't use the sine rule twice; the theta is not the subject of the sine rule in this equation, and therefore can be solved by simply using the missing angle formula for triangles with two known angles.
 

ellurbee

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Ha
Apparently the answer is “75 degrees or 117 degrees”
Though i don't see how it can be 117 degrees considering the question says that theta is acute
Have you heard of the Ambiguous case?
*I'm looking at my notes and Ambiguous means 'not clear' or 'undecided' meaning that B could have two answers- an acute answer or an obtuse answer*
Photo on 30-9-2024 at 1.14 PM.png
 

isho-3

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Ha

Have you heard of the Ambiguous case?
*I'm looking at my notes and Ambiguous means 'not clear' or 'undecided' meaning that B could have two answers- an acute answer or an obtuse answer*
View attachment 44384
yeah this is valid,,,,, but i don't think they'd use an ambiguous case in tests? at least, if they are, it'd be a bit of a dirty trick. the question in the (i'm assuming) textbook is pretty open, and you'd probably have to ask later in the test (if they include something like it) about whether they want you to solve the theta for the given triangle or the given information
 

jane1820

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sina/8 = sin42/6
a = sin^-1(8sin42/6)
a = 63.14...
theta = 180 - 42 - 63 = 75

yeah, it's 75 degrees. for this question, don't use the sine rule twice; the theta is not the subject of the sine rule in this equation, and therefore can be solved by simply using the missing angle formula for triangles with two known angles.
Hmm but why did u do that? (Im not even up to there i just skipped a few chapters to the sine rule so can u educate me a little?)
 

isho-3

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I got 63 degrees
i did the following steps: (also i swear my handwriting looks better on paper 💀)
View attachment 44385
you missed a step; the answer you got is correct, but it's not what you're solving for. you got the 2nd unknown angle in the triangle, but not the value of theta itself. from here you need to solve for theta using missing angles in a triangle w/ 2 known angles (180 - 63 - 42 = 75). basically you weren't wrong in the answer for the other unknown angle (i've dubbed angle 'a' in my solution), but forgot to solve for theta afterwards.
 

jane1820

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you missed a step; the answer you got is correct, but it's not what you're solving for. you got the 2nd unknown angle in the triangle, but not the value of theta itself. from here you need to solve for theta using missing angles in a triangle w/ 2 known angles (180 - 63 - 42 = 75). basically you weren't wrong in the answer for the other unknown angle (i've dubbed angle 'a' in my solution), but forgot to solve for theta afterwards.
what do u mean by ‘value’? Help im lost
isnt when u say (for example) a=3 in an equation doesnt that mean the value of a is 3?
 

sly_lyepat

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I got 63 degrees
i did the following steps: (also i swear my handwriting looks better on paper 💀)
View attachment 44385
You have to solve the angle opposite to the missing side, the angle you just found is opposite to 8 , so minus the answer form the angle you just found from 180 so you do:
180-63-42=75
180(sum of all angles in a triangle)-63(angle you just solved)-42(angle they all ready gave)=75(theta)
 

jane1820

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You have to solve the angle opposite to the missing side, the angle you just found is opposite to 8 , so minus the answer form the angle you just found from 180 so you do:
180-63-42=75
180(sum of all angles in a triangle)-63(angle you just solved)-42(angle they all ready gave)=75(theta)
OHHH IT ALL MAKES SENSE NOW OMG THX 🙏
 

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