Carrotsticks' MX2 HSC 2013 Solutions (1 Viewer)

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
Consider the arg of -1-root(3)i.
hmmm yeah I get what you mean, but how come the answer still comes out?

EDIT: But the question tells you the complex numbers are both in the first quadrant, right?
 
Last edited:

Trebla

Administrator
Administrator
Joined
Feb 16, 2005
Messages
8,392
Gender
Male
HSC
2006
Same here haha. I've forgotten stuff in Chem and Physics, but somehow math is ok.

Oh yeah and bump for the question of course.
Think about the range of the inverse tan function

Maybe a scan of what was written might help?
 
Last edited:

mreditor16

Well-Known Member
Joined
Apr 4, 2014
Messages
3,169
Gender
Male
HSC
2014
Carret, I think there is a typo with Q16 b) v)....

Shouldn't your definition of b be such that b is the length of the semi-minor axis? You define it as the length of the minor axis, which should be 2b, no?

Tell me if I'm wrong :)
 

mreditor16

Well-Known Member
Joined
Apr 4, 2014
Messages
3,169
Gender
Male
HSC
2014
Carret, I think there is a typo with Q16 b) v)....

Shouldn't your definition of b be such that b is the length of the semi-minor axis? You define it as the length of the minor axis, which should be 2b, no?

Tell me if I'm wrong :)
bumpity bump :)
 

Carrotsticks

Retired
Joined
Jun 29, 2009
Messages
9,494
Gender
Undisclosed
HSC
N/A
Carret, I think there is a typo with Q16 b) v)....

Shouldn't your definition of b be such that b is the length of the semi-minor axis? You define it as the length of the minor axis, which should be 2b, no?

Tell me if I'm wrong :)
In which case, it should be "Semi-minor axis". Cheers =)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top