Carrotsticks
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You said that the arg was inverse tan ....Bump. Is my solution valid?
Are you sure this is always true?
You said that the arg was inverse tan ....Bump. Is my solution valid?
wait why isn't it? Sorry i've forgotten a lot over the past two months hahahaYou said that the arg was inverse tan ....
Are you sure this is always true?
hmmm yeah I get what you mean, but how come the answer still comes out?Consider the arg of -1-root(3)i.
Same here haha. I've forgotten stuff in Chem and Physics, but somehow math is ok.wait why isn't it? Sorry i've forgotten a lot over the past two months hahaha
Thanks lol, im still curious as to why i lost two marksOh yeah and bump for the question of course.
Maybe discuss it next week at the meet.Thanks lol, im still curious as to why i lost two marks
Think about the range of the inverse tan functionSame here haha. I've forgotten stuff in Chem and Physics, but somehow math is ok.
Oh yeah and bump for the question of course.
the link is dead.
btw admitri I pm'ed you!
I've updated it =)Why is file gone :{
thanks Carret.I've updated it =)
Thanks for letting me know!
bumpity bumpCarret, I think there is a typo with Q16 b) v)....
Shouldn't your definition of b be such that b is the length of the semi-minor axis? You define it as the length of the minor axis, which should be 2b, no?
Tell me if I'm wrong
In which case, it should be "Semi-minor axis". Cheers =)Carret, I think there is a typo with Q16 b) v)....
Shouldn't your definition of b be such that b is the length of the semi-minor axis? You define it as the length of the minor axis, which should be 2b, no?
Tell me if I'm wrong
okay, thanks for confirming. I just wanted to check I wasn't doing something stupid. thanks!In which case, it should be "Semi-minor axis". Cheers =)