could i teach myself 4unit from the textbook? (1 Viewer)

[tacogym27101990]

lolokay is managing fine.

yeah but his a freak of nature

 

[tommykins]

yeah but his a freak of nature

true, true.

 

[nerdsforever]

Id say yes because it always helps to learn ahead

 

[dux&src]

yeah but his a freak of nature

lolokay

 

[melonkitten]

lolokay is managing fine.

lolokay?

i dont get it

 

[lyounamu]

lolokay?

i dont get it

He is a BoS member who is freak at maths.

 

[shaon0]

lolokay is managing fine.

yeah he's gun at maths

 

[shaon0]

absoulutely no chance.

perhaps complex numbers, or the integration chapter..

but not the whole course

i would disagree....there are some ppl that can learn MX2 themselves and get >95 in the HSC without much work

 

[minijumbuk]

Yeah, you can try. I read my friend's 4u notes on complex numbers just for fun, and I understood them (I do 3u)

The further you get ahead of everyone in the HSC, the better. It's best to finish the course early, and leave plenty of time for revision.

 

[youngminii]

Yeah I'm also going to teach myself 4unit
Also a bit of every other subject
=D Gl

 

[Forbidden.]

integration by parts oh so cool

 

[alcalder]

Since most of Ext 2 Maths is work you need to do yourself and most of it is about the process and not the theory, if you know the theory then no one can teach you the thinking process.

Learning on your own may be take a lot more time from your other subjects, however, so I would be careful. It does help to have a mentor/teacher to run things by and explain the harder concepts from time to time.

 

[shaon0]

could someone help me on the following?

integration~ S (limits~ pi/3 and pi/6) (secx)^2.sinx dx

this is from new senior maths 4unit page108 question 52
thanks

 

[Iruka]

Try the substitution u=cos x

 

[tacogym27101990]

could someone help me on the following?

integration~ S (limits~ pi/3 and pi/6) (secx)^2.sinx dx

this is from new senior maths 4unit page108 question 52
thanks

just remember secx is 1/cosx
so you'll actually be integrating sinx/cos^2x i think

 

[Js^-1]

∫ {Lower limit = pi/6, Upper Limit = pi/3} sec²x . sinx dx
=∫ {pi/6, pi/3} sinx / cos²x dx

Let u = cos x
du = -sin x dx

At x = pi/3 u = 1/2
x = pi/6 u = (√ 3)/2

= - ∫ {1/2, (√ 3)/2} u^-² du
= ∫ {(√ 3)/2, 1/2} u^-² du

= - [1/u] {(√ 3)/2, 1/2}

= 2 - 2/(√ 3)
= (6-(√ 3))/3

 

[tommykins]

could someone help me on the following?

integration~ S (limits~ pi/3 and pi/6) (secx)^2.sinx dx

this is from new senior maths 4unit page108 question 52
thanks

(secx)^2.sinx = sinx/cos²x = secx.tanx

Thus the evaluation of the integral becomes [secx]pi/3->pi/6

 

[shaon0]

∫ {Lower limit = pi/6, Upper Limit = pi/3} sec²x . sinx dx
=∫ {pi/6, pi/3} sinx / cos²x dx

Let u = cos x
du = -sin x dx

At x = pi/3 u = 1/2
x = pi/6 u = (√ 3)/2

= - ∫ {1/2, (√ 3)/2} u^-² du
= ∫ {(√ 3)/2, 1/2} u^-² du

= - [1/u] {(√ 3)/2, 1/2}

= 2 - 2/(√ 3)
= (6-(√ 3))/3

thanks for your help

 

[melonkitten]

i would disagree....there are some ppl that can learn MX2 themselves and get >95 in the HSC without much work

err, if you say so, faggot.

 

[undalay]

thanks for your help

substitution method too long.