Help me integrate this: (1 Viewer)

MATHmaster · May 10, 2012

Integrate:

(x²+3)/2x

SpiralFlex · May 10, 2012

$\int \frac{x^2+3}{2x} \;dx$

$=\int (\frac{x}{2}+\frac{3}{2x})\;dx$

$=\int (\frac{x}{2}+\frac{3}{2}*\frac{1}{x})\;dx$

$=\frac{1}{4}x^2+\frac{3}{2}\ln x+C$

deswa1 · May 10, 2012

$\int \frac{x^2+3}{2x}dx=\int \frac{x}{2}+\frac{3}{2x}dx\\ =\frac{x^2}{4}+\frac{3lnx}{2}+C$

EDIT: Too slow

umm what · May 10, 2012

The power of the numerator is greater than denominator, so u gotta divide x^2 +3 by 2x

MATHmaster · May 10, 2012

Oh kk makes sense now!
Thanks guys

Help me integrate this: (1 Viewer)

MATHmaster

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SpiralFlex

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deswa1

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umm what

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MATHmaster

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