Help! to approach this maths question?? (1 Viewer)

fabl

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:wavey:

A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y)

Find coordinate of D.

I attempted question using distance formula and simultaneous equations but the x and ys kept cancelling each other out.
 

fabl

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A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y) ??

:wavey:

A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y)

Find coordinate of D.

I attempted question using distance formula and simultaneous equations but the x and ys kept cancelling each other out.
 

fabl

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A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y)

A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y)

Find the coordinates of D?

I attempted distance formula and simultaneous equations. But the xs and ys kept cancelling out.
 

iStudent

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The y is 2 (same as co-ord C and drawing the rhombus)
The X is -2+5=3 (length of side is 5. again, using the coord of C and drawing the rhombus)
hence coordinate is (2,3)
 

fabl

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Thankyou, Very Appreciated, your answer was more simple. :)
 

bhatman

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Re: A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y)

Find the midpoint of B(6,6) and C(-2,2) (two opposing vertices)
This midpoint should also be the midpoint of A(1,6) and D(x,y) and you can find it from there
Just looking at it, I think D should be (3,2)
 

braintic

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Re: A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y) ??

The question is not specified well enough. There are three possible scenarios.
Is the rhombus called ABCD, ABDC or ADBC?

Assuming it is ABCD:

A to B is +5 units horizontally.
So D to C is also +5 units horizontally.
So D is (-7,2).
 

Feynman

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Re: A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y)

D has the same y value as C, 2
-2 + 5 = 3 (length is 5)
The coords of D are (3,2)
 

harrowed2

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Re: A rhombus with vertices A (1,6) B (6,6) C (-2, 2) and D (x, y) ??

The question is not specified well enough. There are three possible scenarios.
Is the rhombus called ABCD, ABDC or ADBC?

Assuming it is ABCD:

A to B is +5 units horizontally.
So D to C is also +5 units horizontally.
So D is (-7,2).

It can't be ABCD.
AB=AC=5 but BC=4sqrt5.

So BC must be a diagonal, making D (3,2) , which is 5 units to the right of C.
 
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Trebla

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For future reference please post your question in one forum only, preferably in the appropriate level.
 

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