nightweaver066
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- Jul 7, 2010
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- 2012
bahahaha^, i knew it. nightweaver, just accept it, please.
restating this.parabola
next question:
simplify :
sin(A+B)sin(A-B)+cos(A+B)cos(A-B)
cos(A + B - (A - B))parabola
next question:
simplify :
sin(A+B)sin(A-B)+cos(A+B)cos(A-B)
yeh i typed it up and noticed. But i dont see how that is right.
No no no. You cannot just divide by x and assume that it takes on all real values. As soon as you divide by x you're assuming that it can't equal zero.Consider the straight line y=x. You can multiply the RHS by x/x without changing its value. Thus the straight line becomes y=x^2/x which suddenly can't have a value of 0, even though the line hasn't changed and its still defined at x=0
Yep because x can be any value including zero so multiplying by x/x is erroneousNo no no. You cannot just divide by x and assume that it takes on all real values. As soon as you divide by x you're assuming that it can't equal zero.
Yep, whoops didn't think of that. Why then does wolfram show the curve continuous at 0?Yep because x can be any value including zero so multiplying by x/x is erroneous
Because x=0 is an infinitely small point so barely noticeable.Yep, whoops didn't think of that. Why then does wolfram show the curve continuous at 0?
Is itsorry for turning this thread into a pedantic fest, next question!
solve for x.
e^(2x) - 7e^(x) + 9 > 0 (difficulty: moderately intriguing)
highlight below for the answer:
the answer is in your head
correctIs it
x < Ln(3.5 - sqrt(13)/2) and x > Ln(3.5 + sqrt(13)/2)
lol
What would you say the difficulty is?Given f(x) = arccos(1/x)
State it's domain
Given f(x) = arccos(1/x)
State it's domain