• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

HSC 2013-14 MX1 Marathon (archive) (1 Viewer)

Status
Not open for further replies.

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread

I found a mistake in my working out for the RHS

If i equate coefficients of x^(2n) for [3], i get
I'm pretty sure you get

The n+1th term in that binomial expansion in [3] is
 

JJ345

Member
Joined
Apr 27, 2013
Messages
78
Gender
Female
HSC
N/A
Re: HSC 2013 3U Marathon Thread

I don't think so, I could be wrong but I'm getting what the question sasys.
I'm not getting the +g either for some reason. How did you solve it?
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread

I'm not getting the +g either for some reason. How did you solve it?
Yep I redid and you are right if we take range as distance from projection (which is probably the more correct definition), I took range as distance from origin.
 

Kustom-

New Member
Joined
Jan 28, 2013
Messages
13
Gender
Male
HSC
2014
Re: HSC 2013 3U Marathon Thread

OMG I need help with this stupid question -_-

Prove:
sin(x) + sin(nx) = 2sin (nx/2 + x/2) x cos(nx/2 - x/2)

Please!!
 

Carrotsticks

Retired
Joined
Jun 29, 2009
Messages
9,494
Gender
Undisclosed
HSC
N/A
Re: HSC 2013 3U Marathon Thread

Start with RHS then expand then prove LHS.
 

Kustom-

New Member
Joined
Jan 28, 2013
Messages
13
Gender
Male
HSC
2014
Re: HSC 2013 3U Marathon Thread

see I tried but didn't get toooo far... Im not sure how to expand 2sin(x/2) x sin(x/2) x sin(nx/2) x cos(nx/w)
 

Makematics

Well-Known Member
Joined
Mar 26, 2013
Messages
1,829
Location
Sydney
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread

argh so tempting to use 4U sum to product rules for that haha
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread





 

Kustom-

New Member
Joined
Jan 28, 2013
Messages
13
Gender
Male
HSC
2014
Re: HSC 2013 3U Marathon Thread

nope, im not sure they are correct haha.. i expanded too 2sin(nx/2)cos(x/2) + cos(nx/2)2sin(x/2) x cos(nx/2)cos(x/2) + sin(x/2)sin(nx/2)
then from there did 2sin(nx/2)cos(nx/2) x cos(x/2)Cos(x/2) and got sin(nx)cos^2(x/2) and left with c0s(nx/2)2sin(x/2) x sin(x/2) sin(nx/2)
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread



 
Last edited:

Menomaths

Exaı̸̸̸̸̸̸̸̸lted Member
Joined
Jul 9, 2013
Messages
2,373
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread

Imagine Sy's been getting other people to do his homework for him
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread

Are you missing an m/(1!) ? (I don't know - I haven't done the question. But it looks like a term is missing.)
I got that question from Summation of Series - Jolley, series number 196.
I'm pretty sure the 1 cancels out which is why it's there

EDIT: Let me redo it I may have made a mistake

Imagine Sy's been getting other people to do his homework for him
hahahahaha
 
Last edited:

JJ345

Member
Joined
Apr 27, 2013
Messages
78
Gender
Female
HSC
N/A
Re: HSC 2013 3U Marathon Thread

I got that question from Summation of Series - Jolley, series number 196.
I'm pretty sure the 1 cancels out which is why it's there
I showed the result but having the m/1! was necessary---> Are you sure there isn't a mistake? I may be wrong though.
 

Sy123

This too shall pass
Joined
Nov 6, 2011
Messages
3,730
Gender
Male
HSC
2013
Re: HSC 2013 3U Marathon Thread

Sorry you are right braintic, I am missing a m/1!, I apologise, fixing now.
 
Status
Not open for further replies.

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top