Sy123
This too shall pass
- Joined
- Nov 6, 2011
- Messages
- 3,730
- Gender
- Male
- HSC
- 2013
Re: HSC 2013 4U Marathon
Do the same for n = 2k+1, and we then prove that:
for all n, therefore it is the sequence of Fibonacci numbers.
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Do the same for n = 2k+1, and we then prove that:
for all n, therefore it is the sequence of Fibonacci numbers.
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