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HSC 2013 MX2 Marathon (archive) (1 Viewer)

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SpiralFlex

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Re: HSC 2013 4U Marathon

For the last Q I posted a hint is the triangular inequality.
 

Ikki

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Ikki

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Re: HSC 2013 4U Marathon

Put a new 2014 thread? I dislike years getting mixed up =[









Triangle Inequality eh spiral? Lets play around with the stuff which is given...



Idk feels shifty... Did I assume anything? (Can u say those things from triangle ineq?)
Am I on the right path?
 
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seanieg89

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Re: HSC 2013 4U Marathon

LOL nice one, caught on technicality? But pretty sure it's referring to fermat's last theorem. Where n must also be an integer.
haha obviously a counter-troll.
 

hit patel

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Re: HSC 2013 4U Marathon

Thankyou :)





Clearly no one pays attension to the new guy LOL :p
You talking about yourself? I had invaded this forum since term 3. But hey nice to meet you. Its all good hahaha :)
 
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hit patel

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Re: HSC 2013 4U Marathon

Good to meet you too lol. All good bro :p
Hahaha U asked for question, Here i post one:

Use demoivre theorem to find tan7x in terms of tan x. (3)
Find the Value of cot^2 (pi/7) + cot^2 (2pi/7) + cot^2 (3pi/7). (6)

Note: I didnot make this question and therefore yields correct and valid answers.
 

Ikki

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Re: HSC 2013 4U Marathon

Hahaha U asked for question, Here i post one:

Use demoivre theorem to find tan7x in terms of tan x. (3)
Find the Value of cot^2 (pi/7) + cot^2 (2pi/7) + cot^2 (3pi/7). (6)

Note: I didnot make this question and therefore yields correct and valid answers.
Alright, lets do this :p
[1]
Find tan7x in terms of tanx.











Divide Imaginary by Real:



DIVIDE EVERYTHING BY COS^7(X) :)



YAYYYAYAYAYAYYAYAYYAYAY. Screw the next question, I'll look at it later LOL.
 
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Sy123

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Re: HSC 2013 4U Marathon






As for an update on compilation process, I'm up to page 63 right now, its a much longer process than I thought (mostly because I need to make sure the questions are solvable)!
 

obliviousninja

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Re: HSC 2013 4U Marathon






As for an update on compilation process, I'm up to page 63 right now, its a much longer process than I thought (mostly because I need to make sure the questions are solvable)!
gj Sy.
 

nightweaver066

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Re: HSC 2013 4U Marathon






As for an update on compilation process, I'm up to page 63 right now, its a much longer process than I thought (mostly because I need to make sure the questions are solvable)!
Are you sorting by topic too?
 

Fawun

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Re: HSC 2013 4U Marathon

sigh 4u is going to fuck me up
 

Ikki

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Re: HSC 2013 4U Marathon






As for an update on compilation process, I'm up to page 63 right now, its a much longer process than I thought (mostly because I need to make sure the questions are solvable)!
What exactly are you compiling?

------
If i let z=x+iy and expand...


Now logically, if it was to be purely imaginary then, the real part would equal to zero right?






I know i screwed up somewhere...

-------
If its purely imaginary for |z|=2, then.....


Now, let real=0



I have a feeling i'm thinking in the wrong way for these questions...
 

Sy123

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Re: HSC 2013 4U Marathon

What exactly are you compiling?

------
If i let z=x+iy and expand...


Now logically, if it was to be purely imaginary then, the real part would equal to zero right?






I know i screwed up somewhere...

-------
If its purely imaginary for |z|=2, then.....


Now, let real=0



I have a feeling i'm thinking in the wrong way for these questions...
Yep for the first it is |z| = 1, not sure how you got to z=+- 1 though, z can be complex as well (for example, as an excercise try putting z=1/2 + sqrt(3)/2 i in that function, it should output a purely imaginary number)

For the second one, try thinking of a function similar to the first one.
 

Ikki

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Re: HSC 2013 4U Marathon

Yep for the first it is |z| = 1, not sure how you got to z=+- 1 though, z can be complex as well (for example, as an excercise try putting z=1/2 + sqrt(3)/2 i in that function, it should output a purely imaginary number)

For the second one, try thinking of a function similar to the first one.
Jazu... Um... i'm going to go out on a limb and say...


Well... It seems to work using the previous working out...
 
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Sy123

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Re: HSC 2013 4U Marathon

Jazu... Um... i'm going to go out on a limb and say...


Well... It seems to work using the previous working out...
Replace the sqrt(2) with 2 and its correct :)

The proper way to do it is just consider:



We know that it is purely imaginary for



Therefore it is purely imaginary for
 
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