We know from diagram (triangle inside the circle):
You have made a mistake in your first line, Q is the intersection between the 2 chords, not P.We know from diagram (triangle inside the circle):
APxPQ=BPxPC
Working backwards from what to prove:
BPxPC=PQx(PB+PC)
BPxPC=PQxBC
If we equate what to prove and what we know:
BC=AP? But BC=AB
so, AB=AP which makes no sense. (Does not necessarily have to be true and shouldn't)
This is what i did:You have made a mistake in your first line, Q is the intersection between the 2 chords, not P.
So from your proof it now is:
AQ x QP = BQ x QC
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I can reveal my proof if you wish, or I can let you have another go
Yep well done, this was my proof:This is what i did:
Yes I got this as wellI got 18/7?
Hey dunjaa and Sy do one of you think you could explain part i of this answer to me? I understand the rest of it but can't quite follow the first step. Thanks.View attachment 30662 Nice proof!
His solution to part (i) is wrong.Hey dunjaa and Sy do one of you think you could explain part i of this answer to me? I understand the rest of it but can't quite follow the first step. Thanks.
Yea I did it via angles as wellMy solution was ugly but I got OB^2=26cm. Yeah, I went brute force with angles, I'm trying to think of a more elegant geometrical solution.