# Inequality why? (1 Viewer)

#### Tryingtodowell

##### Member
For this inequality question why is one equal to and the other not?? I tried got both equal to how do u figure this

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#### Average Boreduser

##### π±πππππ
For this inequality question why is one equal to and the other not?? I tried got both equal to how do u figure this
look on the graph bro two branches one where theres an asymptote and one intersection where x=1. If theres an asymptote, theres no chance of it =ing to -1. Also just observe the denom x+1, so x=/-1

#### Tryingtodowell

##### Member
look on the graph bro two branches one where theres an asymptote and one intersection where x=1. If theres an asymptote, theres no chance of it =ing to -1. Also just observe the denom x+1, so x=/-1
im sorry dont get it

#### Average Boreduser

##### π±πππππ

Note theres an asymptote at x=-1. Hence, the inequality cannot include x=-1

#### Average Boreduser

##### π±πππππ
fast way to notice this is by observing the denominator. If x was -1 in that inequality you provided, you would get 2/0= infinite, which would obviously not satisfy the inequality. Therefore we do not include the x=-1 case.

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#### Tryingtodowell

##### Member
fast way to notice this is by observing the denominator. If x was -1 in that inequality you provided, you would get 2/0= infinite, which would obviously not satisfy the inequality. Therefore we do not include the x=-1 case.
I just started year 11 and ur throwing all these terms on me .

#### Average Boreduser

##### π±πππππ
I just started year 11 and ur throwing all these terms on me .
how much dyk on graphs currently?

#### Tryingtodowell

##### Member
If someone could explain the question above in simple terms It would be appreciative

#### wollongong warrior

##### Member

Isn't this comment also applicable to your main question?

#### eternallyboreduser

##### Well-Known Member
Nevermnd dont waste time on me
sorry but u cannot be fr rn hes tryna help you and youre rejecting it what???

#### Aeonium

##### βi love sylviab 123
I just started year 11 and ur throwing all these terms on me .
$\bg_white \frac{\text{numerator}}{\text{denominator}}=\text{numerator}\div\text{denominator}$ (the other words should make sense)
If someone could explain the question above in simple terms It would be appreciative
denominator can never be 0 as, well, how do you divide by infinity? you can't. so it's an asymptote.
???

#### eternallyboreduser

##### Well-Known Member
just multiply both sides by the denominator squared, note that denominator cannot equal 0

#### wollongong warrior

##### Member
Just to clarify, you're asking why $\bg_white x < -1$ and not $\bg_white x \leq -1$?

#### eternallyboreduser

##### Well-Known Member
Just to clarify, you're asking why $\bg_white x < -1$ and not $\bg_white x \leq -1$?

#### Tryingtodowell

##### Member
Just to clarify, you're asking why $\bg_white x < -1$ and not $\bg_white x \leq -1$?
yeah and why the other has the equal to sign

#### eternallyboreduser

##### Well-Known Member
yeah and why the other has the equal to sign
its cos x=-1 is an asymptote, thus not part of the solution