Preliminary mathematics marathon (1 Viewer)

[hscishard]

x^2 -1
You're askingh for the general one, arent you?

 

[random-1005]

x^2 -1
You're askingh for the general one, arent you?

yes


in normal quadratic form, sqaured term, linear term and constant =0

 

[hscishard]

What terms should be in there?

 

[random-1005]

What terms should be in there?

p's and q's obviously

 

[Rezen]

 

[edmundsung]

i know it's easy for u guys...
but i still don't know how to solve it by multiplying the square of the denominator.
greatly appreciated if someone can help

 

[random-1005]

i know it's easy for u guys...
but i still don't know how to solve it by multiplying the square of the denominator.
greatly appreciated if someone can help

mmm hsc 2012, looking to get a head start?

First step: exclude values where denominator=0 { however, you will see this only matters when you have a "less than or equal" or a "greater than or equal"}

(2x+5)(x+1)^2 / (x+1) < 3(x+1)^2 { DONT EXPAND, it is easier to move all terms to one side and factorise, saves time}
(2x+5)(x+1)-3(x+1)^2 <0
(x+1) { (2x+5) -3(x+1) } <0
(x+1)( 2-x) <0
x<-1, x > 2 ( if you need explaination from the previous step to this one please ask)

 

[ohexploitable]

 

[edmundsung]

mmm hsc 2012, looking to get a head start?

First step: exclude values where denominator=0 { however, you will see this only matters when you have a "less than or equal" or a "greater than or equal"}

(2x+5)(x+1)^2 / (x+1) < 3(x+1)^2 { DONT EXPAND, it is easier to move all terms to one side and factorise, saves time}
(2x+5)(x+1)-3(x+1)^2 <0
(x+1) { (2x+5) -3(x+1) } <0
(x+1)( 2-x) <0
x<-1, x > 2 ( if you need explaination from the previous step to this one please ask)

thank you so much

 

[t00l]

shat brix

 

[hscishard]

For some reason, I don't think that's correct

 

[Rezen]

If thats not enough proof i can think of two other methods to derive the polynomial.

 

[nat_doc]

x^2 -q=0

sum or roots of new equation is 0 and product is: -(a-b)(a-b) =-(a-b)^2= -sqrt(P+q-4abc+2sin\theta) *using the guassian distribution formula*
then upon inspection, product of roots = -q thus x^2 -q=0

 

[ohexploitable]

New Question:

 

[random-1006]

New Question:

thats not hard, just long, get some interesting questions lol

 

[ohexploitable]

thats not hard, just long, get some interesting questions lol

The trick is to find a shortcut, it can be done in a few lines.

 

[random-1006]

The trick is to find a shortcut, it can be done in a few lines.

lol what expand ( p -a) ( p-b) (p-c) ( p-d), where a, b, c, d are roots


its a little less work i guess

 

[ohexploitable]

lol what expand ( p -a) ( p-b) (p-c) ( p-d), where a, b, c, d are roots


its a little less work i guess

I felt special because I was the only one in class who thought of that.

 

[random-1006]

I felt special because I was the only one in class who thought of that.

lol why the

 

[ohexploitable]

Re: another question

Much fun was had in this thread.

Quick, someone post a new question!