Section I - Multiple Choice (1 Viewer)

[barbernator]

But why not C

e^-x^2 is always < 1 for all x

 

[Aysce]

Mc is looking good =)

 

[7eleven]

e^-x^2 is always < 1 for all x

Yaaaaaaay
So i got 10/10 for MC then

 

[Zeroes]

10 is c confirmed by my teacher too.

My teacher confirmed B.

Awkward.

 

[Aysce]

Yaaaaaaay
So i got 10/10 for MC then

HI-5*

My teacher confirmed B.

Awkward.

You realise he's a troll right? haha

 

[deswa1]

Why are we still discussing 10 lol- its definitely B. A and D are odd between symmetrical limits so they don't work and C is below the y axis for all x in the domain.

Though I only got 9/10 for MC - I put C for Q8.

 

[7eleven]

HI-5*



You realise he's a troll right? haha

Hi5 Back* lol

 

[lolcakes52]

I got
1 D
2 A (apparently wrong but i don't know)
3 A
4 A
5 C
6 A (wrong, im an idiot)
7 A
8 B
9 C
10 B http://www.wolframalpha.com/input/?i=integrate x^3sin(x) from -pi to pi

 

[someth1ng]

This is what I have, they should be mostly correct:
1. D
2. D
3. A
4. A
5. C
6. B
7. A
8. B
9. C
10. B

For Q10, I didn't know how to solve it...so what I did was sub in the limits twice, whichever showed two positive numbers was my answer (B).

 

[lonelynight99]

This is what I have, they should be mostly correct:
1. D
2. D
3. A
4. A
5. C
6. B
7. A
8. B
9. C
10. B

For Q10, I didn't know how to solve it...so what I did was sub in the limits twice, whichever showed two positive numbers was my answer (B).

I think 3=C coz it conjugate of z not z

 

[Nooblet94]

This is what I have, they should be mostly correct:
1. D
2. D
3. A
4. A
5. C
6. B
7. A
8. B
9. C
10. B

For Q10, I didn't know how to solve it...so what I did was sub in the limits twice, whichever showed two positive numbers was my answer (B).

This is why MC is a stupid idea. You can just get lucky.

 

[someth1ng]

I think 3=C coz it conjugate of z not z

It's A as discussed before. If you actually sub in, i(x-iy), it becomes y+ix and so, what you do is swap x and y. This makes it A.

 

[someth1ng]

This is why MC is a stupid idea. You can just get lucky.

Works - had a tiny bit of logic behind it LOL

 

[kman16]

My results:
1. D
2. D
3. A ITS "A". Conjugate Z is a reflection about the x-axis. Then multiplication of "i" rotates it 90degrees anticlockwise.
4. A
5. C
6. B
7.A
8. A
9. C
10. B B is the only even funtion which will give a positive area.

Now that i look back on it I've realised that Q8 is B. Looks like a 9/10 for me

 

[marksgm]

Bbcbbcbbcb

 

[mraznboy]

Can someoneUpload the mc?

 

[simskee]

1.d 2.d 3.a 4.a 5.c 6. B 7. A 8.b 9. C 10.b

 

[The Sped]

are they correct?

 

[SuperSemen]

3 is definitely A, just sub in numbers, i.e z = 1 + i => conj z = ( 1 - i )i = i + 1 , still in first quad.

 

[ademb13]

the last one was b. all integrals are odd except that one, which is even and the integral will be greater than 0