OK for eg
1) find the area of the minor segment if radius is 1.5m and the angle subtended is 0.43
2) find the area of the minor segment if radius is 7.2mm and the angle subtended is 55 degrees.
3) find the area of the minor segment if radius is 2.1 m and the angle subtended is 82° 35'
4) find the area of the minor segment if radius is 3cm and angle is subtended at π/7
Salaam'ulaikum !
Area of segment = area of sector - area of triangle
= 0.5 x r^2 x @ - 0.5 x r^2 x sin @
= 0.5 x r^2 x (@ - sin @)
[ here the angle @ must be in radians - not degrees]
1) r = 1.5 m and @ = 0.43 radians
segment area = 0.5 x 1.5^2 x (0.43 - sin(0.43)) = 0.01477 m^2
just sub in and give results in m^2 units
2) r = 7.2 mm @ = (55/360) x 2 x pi radians
give results in mm^2 units
3) r = 2.1 m 35' = 35/60 deg = 0.58333 .. @ = (82.58333../360) x 2 x pi rads
Give results in m^2 units
4) Nothing could be easier since @ already given = pi/7 rads and r = 3 cm
give results in cm^2 units
If formula I gave is wrong, then all your answers will be wrong of course!