addikaye03
The A-Team
Isn't that the common perception of physics from exterior?this is making me regret not picking physics, sigh, if only i knew it was a whole lot of math
Isn't that the common perception of physics from exterior?this is making me regret not picking physics, sigh, if only i knew it was a whole lot of math
Probably not. But everybody has different preferences.Yeah, I doubt too many people could do 0.866 x 1.6x10^16 in their heads. Nor would you be able to do the electron motion question. Nor Kepler's Third Law.
if you can survive w/o a calculator, its your own businessThat was uncalled for.
I find it amazing that many people believe that it's impossible to do such calculations presented in the 2009 HSC Physics paper without using a calculator.
May I repeat again that in HSC level Physics you can be a decimal or so off and still get the marks PROVIDED THAT YOU SHOWED ALL WORKING.
I find it easier not using a calculator, if you find it easier using a calculator, then good for you. I don't like using calculators obviously, I don't know why people have such a problem with that. It's just personal preference... you don't see me having a go at people for actually using a calculator.
Probably not. But everybody has different preferences.
Uhh no they wont because judging by everyone's answers here I got the same answer.lol, i bet the markers will have a laugh at your paper.
No... I can't use one (ie. not good at using one). I thought you would've established that by what I've said.you are too good for a calculator?
Complex numbers in Physics??? No way ... I thought I'd have some fun there.complex multiplications
Uhh no they wont because judging by everyone's answers here I got the same answer.
No... I can't use one (ie. not good at using one). I thought you would've established that by what I've said.
Complex numbers in Physics??? No way ... I thought I'd have some fun there.
Hmmm, how did you do the length contraction in your head?
The speed was like 0.99999c wasn't it? I don't remember the rest length.Hmmm, how did you do the length contraction in your head?
No, technically you should go by the greatest amount of significant places given in the data. ie. Since you are given that c=3*10^8 you can only go to 1 sig fig, as far as I know (even though you were given 0.99999c).Well technically, you should go to the greatest amount of decimal places given in the Q, e.g. speed of particle is 0.899c, length is 0.8. you go to 3 d.p
So my Q follows, how do you go to 3dp+?
I'm sorry, but that is fucking bullshit. Obviously you're serious.The speed was like 0.99999c wasn't it? I don't remember the rest length.
I don't see what's so hard about it. (0.99999)^2 is obviously going to be a little bit less than 0.99999 (I'd guess that it'd be about 0.99998 or 0.99997).
And then taking the square root would be the easy part.
What is BS?I'm sorry, but that is fucking bullshit. Obviously you're serious.
Ok so then you go 1-(0.99999)^2= 0.00002
So now, whats the square root of 0.00002? Explain to me how you would do that?
*sigh* ....as I said earlier at HSC level it doesn't matter aslong as you've shown all working...Well, unfortunately for you, 4.5 x 10^-3 x the length (1.7x10^5), does not give you the 760.26 light years (or even 760) required. It gives you 765.
\*sigh* ....as I said earlier at HSC level it doesn't matter aslong as you've shown all working...