Is it because:
Let b=0
Assume b^b=x
b.ln(b)=ln(x)
0.ln(0)=ln(x)
And ln(0) is undefined since x=0 is an asymptote in a natural logarithmic function.
Thus, 0.Undefined=Undefined.
Therefore, 0^0 is undefined.
---I'm just wondering..
Let b=0
Assume b^b=x
b.ln(b)=ln(x)
0.ln(0)=ln(x)
And ln(0) is undefined since x=0 is an asymptote in a natural logarithmic function.
Thus, 0.Undefined=Undefined.
Therefore, 0^0 is undefined.
---I'm just wondering..