That rule applies after all the other rules don't work(i.e more than 1 answer). In this case Cl comes first alphabetically... I would have gone for OP's answer but I don't know anymore...I think it's because you give lowest numbers to most electronegative halogen: F>Cl>Br>I
Oh my bad Forgotten my chemistry :\That rule applies after all the other rules don't work(i.e more than 1 answer). In this case Cl comes first alphabetically... I would have gone for OP's answer but I don't know anymore...
No One could answer this easy question and your also wrong! Learn to study smart, you had to memorise the rules of naming them! It took me 1 second to work out the answer
"Assemble the components into a complete name, with the halogen and side groupNo One could answer this easy question and your also wrong! Learn to study smart, you had to memorise the rules of naming them! It took me 1 second to work out the answer
lol the answer is c, because the chlorine is on the 5 carbon while the fluorine is on the 3 carbon. so alphabetical chloro comes first followed by fluoro, so the answer is:
c) 5-chloro-3-fluoroheptane. Note that: Heptane means 7 carboon, don't confuse your self in HSC!
you are confusing option A with C, option A is right, but alphabetical the numbers are opposite. In Option A you can see, that Chlorine is not on the 3 carbon. Hence option is a is wrong.
It's not left-to-right with nomenclature, that's just the way they're often drawn as a convenience. If you swapped the to halogen groups around on this particular molecule and just flipped it around you'd get the exact same one, so it is the same molecule. (this wouldn't apply if the two halogens weren't equidistant to the end of the carbon chain).No One could answer this easy question and your also wrong! Learn to study smart, you had to memorise the rules of naming them! It took me 1 second to work out the answer
lol the answer is c, because the chlorine is on the 5 carbon while the fluorine is on the 3 carbon. so alphabetical chloro comes first followed by fluoro, so the answer is:
c) 5-chloro-3-fluoroheptane. Note that: Heptane means 7 carboon, don't confuse your self in HSC!
you are confusing option A with C, option A is right, but alphabetical the numbers are opposite. In Option A you can see, that Chlorine is not on the 3 carbon. Hence option is a is wrong.
I was taught this wayI think it's because you give lowest numbers to most electronegative halogen: F>Cl>Br>I
No. OP is correct. Look at the 2012 HSC. Look at question 12 and the answer given by board of studies.I was taught this way
And never got any of these questions wrong
So I'd go with this