a i) Barium
Another good one to distinguish between Pb2+ and Ca2+ is to add hydroxide - if a (white) ppt forms, Pb2+ is present, if not, Ca2+ is presenta i) Barium
a ii) Add sulfate ions (barium sulfate) until a white precipitate forms, if a precipitate forms, then barium is present.
b) To test for Lead add iodide ions (lead iodide), if a yellow precipitate forms, then lead is present. Keep adding until there is no more lead present in the solution. To test for the presence of Calcium, conduct a flame test or add carbonate ions (calcium carbonate), if you conducted a flame test, then you should observe an orange/red flame, if you added carbonate ions, then a white precipitate should form. Sorry I couldn't include equations
Potasium iodide not lead iodide....a i) Barium
a ii) Add sulfate ions (barium sulfate) until a white precipitate forms, if a precipitate forms, then barium is present.
b) To test for Lead add iodide ions (lead iodide), if a yellow precipitate forms, then lead is present. Keep adding until there is no more lead present in the solution. To test for the presence of Calcium, conduct a flame test or add carbonate ions (calcium carbonate), if you conducted a flame test, then you should observe an orange/red flame, if you added carbonate ions, then a white precipitate should form. Sorry I couldn't include equations
This questions been asked so many times look up for solutions
I think it refers to contaminants preventing the catalyst from functioning optimally. For the Haber process, the iron oxide catalyst uses adsorption. If the reaction vessel is contaminated, the catalyst cannot work properly as the reactants cannot interact with the catalyst to produce the products.
Actually it is lead iodide that forms a bright canary yellow, potassium iodide shouldn't form a precipitate, as potassium is a group 1 element.
You mix potassium iodide in the solution and if it turns yellow it confirms lead precipitate.
Poisoning refers to heating im pretty sure youre talking about contaminationI think it refers to contaminants preventing the catalyst from functioning optimally. For the Haber process, the iron oxide catalyst uses adsorption. If the reaction vessel is contaminated, the catalyst cannot work properly as the reactants cannot interact with the catalyst to produce the products.
Not sure what reaction is happening in this picture, but it looks to be the same concept.
But he didn't say add lead iodide, nor did he say add potassium iodide. All he said was add iodide ions, which is enough as he is just explaining the process of identification of lead ions in solution.
This wouldnt get him the marksa i) Barium
a ii) Add sulfate ions (barium sulfate) until a white precipitate forms, if a precipitate forms, then barium is present.
b) To test for Lead add iodide ions (lead iodide), if a yellow precipitate forms, then lead is present. Keep adding until there is no more lead present in the solution. To test for the presence of Calcium, conduct a flame test or add carbonate ions (calcium carbonate), if you conducted a flame test, then you should observe an orange/red flame, if you added carbonate ions, then a white precipitate should form. Sorry I couldn't include equations
He just put the brackets in to show the product forming... He did the same thing for the previous part with barium sulphate.
By saying iodide ions you're asserting that i can use any other ion with it in the reaction
Yes you can. You can use potassium iodide, ammonium iodide, sodium iodide.
Lol why would you add a precipitate to cause another precipitate. If you are going to cause a precipitation, you wouldn't add another precipitate as nothing will occur, that's a no-brainer...
