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Ok so they say it grows at a rate proportional to the population, hence you can derive an equation for the population (lets say 'P') in terms of its intial population (A) and growth rate at a time t. The description they give mathematically translates to dP/dt = kP (where k is a constant which...

Please do not spam the board with your issues with moderators. Like I indicated, if you have an issue take it to the relevant administrator. It serves no purpose posting it here since your concerns will unlikely be seen by them.

I wouldnt say it is, I was averaging 93% internal and then i got a nice surprise once a real external test ie. the trials came :uhhuh: This subject is weird, you can get a whole bunch of questions right out of left field, but then equally you can get a bunch of straight forwards ones. Quite...

Closed due to it being a repeat of the other thread

No, completing year 12 means you have a certificate from the Board of Studies saying you satisfactorily completed year 12

hmm my error is 81000314 service temporarily unavailable

Judging from the posts at this time last year, science faculty marks wont be back until 14th-15th

I know I got a Distinction in ARIN1000 final exam from the lecturer but they havent posted it yet.

double variable calculus is even more fun :D

Haha I will get to it. Lately ive been staring at these usyd maths competition questions

Hahaha damnit i just saw the question now. The fact that SeDaTeD got it in 30 mins is not surprising :) Oh well i have plenty of questions to keep me occupied until the start of 2nd semester

Was that really required?

er whats the 2nd question?

Did they give a reason?

My initial reactions when i first got the questions was that q 1 - 4 looked suspiciously easier to do than i thought they were. I havent looked at it since then.

My school was a Catholic school, and the overall performance was pretty strong due to the fact that they offered Catholic Studies at the same time, hence anyone that didnt want SOR could just take Catholic Studies, most of whom bludged through it.

f(x) = (x - 2)/(x + 2) and f-1(x) = -2(x+1)/(x-1) to find f-1(f(x)), for every x in f-1(x), you sub in f(x). ie. f-1(f(x)) = -2(f(x) + 1)/(f(x) - 1) = -2[(x - 2)/(x + 2) + 1]/[(x - 2)/(x + 2) - 1] = -2[(x - 2 + x + 2)/(x+2)]/[(x - 2 - x - 2)/(x + 2)] = -2[2x/(x+2)]/[-4/(x+2)] =...

Admins, supermods and about 4 or so normal moderators have banning powers

Computer Science @ unsw has a Computer Game Design & Construction major

SOFT 1902 :D