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heres the solution. Its one of those substitution questions.

what is this "3" ?

How come your workings so simple? Please tell me you have some secret to doing it quickly. It took me ages.

GRRRRRRR i spent 10mins typing it up on microsoft equation editor and something happened #$%@. I ended up with 22/7 - pi. But is there an easier method to do this other than expanding the numerator and then dividing out? I dont understand the second part. Because the integral doesnt equal zero...

Relations and functions is a 2u topic. You should really post in the mathematics forum and not the ext 2. I dont see the big deal though, maths is maths.

From personal experience, it really pays off. I failed my trials (below 50%) but aced the actual HSC so my assessment mark was pulled up by alot. In fact, i ended up with an e4 band. So my advice is, stick to it. Do as well as you can for now and just study your ass off before by HSC by doing...

It isnt that much different then when the focus is at the origin. Draw the picture if you get stuck?

If you keep memorising formula, you just confuse yourself. Think of h as the difference between one function value and another. (its width). so if its 3 function values between 1 and 2 obviously your function values are 1, 1.5 and 2 so the distance between 1 and 1.5 is 0.5. if it were 5 fuction...

There isnt an easy method to do these questions, just draw a table of values up and try not to skip any steps because you might make an error. integral = h/3(ends + 4(odd) + 2(even). Im assuming the questions asking you to use 3 function values. It becomes a little too difficult otherwise.

From what little 4u ive done, i dont think there is a method of sketching the curve directly from looking at it .Unless your adept at factorising equations in your head, youd have to do it on paper to find the roots.

I got 94.. a couple of marks lower than what I was hoping for. And for 3u I got 45, again a lil lower than what I expected (doing it again this year)

I did it when i was in year 10 (2002). Then again in 2003 to get a higher mark (and also ext 1 this year too). Hell if i wanted i could do it again this year giving me 3 shots at 2u maths :D Thats the good thing about it, stuff it up do it again. However, you should really ace it the first time.

No, i meant the second dot point question :) You cant really "discuss problems produced by the limited range of the electromagnetic spectrum available for communication purposes" Discuss is for and against, but the question directs you to focus on the against i.e. problems. It should really be...

Nevermind, I found it. I forgot the chain rule when differentiating (lnx)^n. Thanks for everyones help?

Can someone help me find my error? (q47 of ex 33f from fitzpatrick). The first line of my solution isnt mathematically correct, i know. should read d/dx of (1/m+1)*x^m+1 not d/dx of x^m

To date, weve done complex numbers, polynomials, integration and volumes. Teacher says we wont start anything else till next term. So that leaves a few weeks to do the drill.

If you do 4u, you dont do 2u at all. That means your ext 1 and ext 2 marks are doubled.

you have to get accepted into 4u? cant you just decide to do it

WAH? the conjugates just 1-i so z + conj. z = 2 Re z i.e. 1 + i + 1 - 1 = 2

Im pretty sure that this is from the world communicates topic. That second point is badly worded but just to add on to rahul's stuff for advantages: -EM communication (usually of wavelengths longer than light) is the fastest form of communication (EM waves travel at the speed of light). -EM...