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yeah, its probably a harder 2unit application. From what i remember of the 2unit course, these types of questions are usually used in conjunction with the trapazoidal or simpsons rule.

Ive never had a tutor but what Ive seen from those people who do have tutors is that its a complete waste of time/money. A few hours a week paying someone to set you more homework... your time would be better invested in buying a few textbooks and learning things on your own. Personal...

This doesnt seem like a 2unit job

calcium carbonate (limestone) comes to mind. Can't you just use metallic oxides, of which there are many?

thats the exact thing i did! (maybe his from my school). schools who choose to accelerate students usually do school cert in year 9, 2u and 3u prelim in year 10 and 3u and 4u hsc in year 11.

b) nCr = n-1 C r-1 + n-1 Cr LHS = n!/(n-r)!(r)! RHS = (n-1)!/(n-1-r+1)!(r-1)! + (n-1)!/(n-1-r)!(r)! = (n-1)!/(n-r)(n-r-1)!(r-1)! + (n-1)!/(n-1-r)!(r)(r-1)! = [(n-1)!/(n-r-1)!(r-1)!][1/n-r + 1/r] = [(n-1)!/(n-r-1)!(r-1)!][(r)/r(n-r) + (n-r)/r(n-r)] = [(n-1)!/(n-r-1)!(r-1)!][n/r(n-r)] =...

I think its about $2000 a year for my school

s^2/(s+1)^3 = a/s+1 + b/(s+1)^2 + c/(s+1)^3 s^2 = a(s+1)^2 + b(s+1) + c @ s = 0, LHS = 0, RHS = a + b + c @ s = -1, LHS = 1, RHS = c :. c = 1 @ s =1, LHS = 1, RHS = 4a + 2b +c 4a+2b = 0 and a+b = -1, solve simultaneously to get a = 1, b = -2 and c you already have :. s^2/(s+1)^3 =...

im guessing thats (x^2+x+3)/ 3x^5 If so, just split the fraction up into x^2/3x^5 + x/3x^5 + 3/3x^5 which becomes 1/3x^3 + 1/3x^4 + 1/x^5. change to index and then integrate that.

(Sec^2@ -1)(1-sin^2@) = (tan^2@)(cos^2@) =(sin^2@/cos^2@)(cos^2@) =sin^2@

Im not sure why you got 3pi but heres the solution

Out of the list of topics given, id say permutations and combinations are the hardest (especially the proof type questions) Overall though, bionomial theorem/probability and projectile motion to a lesser extent are in my opinion the most challenging topics in 3u.

youll find that alot of selective schools accelerate in 4u maths. ruse is one surprising exception.

Yeah, i dropped it after prelim...

Oh yeah, i think i remember doing something like that before just didnt see it this time. I had this question in a complex numbers test a couple of months ago. Its pretty similar (little more interesting i think) if w is a complex root of z^3 = 1 i) show that w^2 + w + 1 = 0 ii) prove...

(1 + w)(1 + w^2)(1 + w^4)(1 + w^8) = (1 + w)(1 + w^2)(1 + w)(1 + w^2) = [(1+w)(1+w^2)]^2 = (1+w+w^2+w^3)^2 = (2 +w + w^2)^2 =(2 - 1)^2 =1 is that right?

Looks like economics to me

or are you talking about the fundamental identity ones. (sin[x])^2 + (cos[x])^2 = 1 divide both sides by (sin[x])^2 to get 1 + (cot[x])^2 = (cosec[x])^2 or dividing by (cos[x])^2 to get (tan[x])^2 + 1 = (sec[x])^2

i think im worse. ive had the same teacher for year 9 - 12 maths. this includes all the lunch time accelerated lessons and afterschool ones since year 9 (i.e. SC in year 9, 2u in year 10, 3u last year)

is series and sequences assumed knowledge? I thought it was part of the 2u HSC course.