For k = 0, 1, 2, 3, 4, 5, ..., n, Pk (k term) is defined as:
Pk = nCk . a^k . (1-a)^(n-k) where a is real and n>0.
Prove that "Sigma notation" (k=0 on the bottom with n on top) Pk = 1
I just tried it and I cannot seem to get my mind around this. Any helpn will be greatly appreciated...