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The article is dated December 2004. The games tested there are the latest games available at that time. Then F.E.A.R. came out and ruined all the rules. I_F

They're very busy boys down at the Technical Committe on Scaling. It's a general look, but that's how they decide to scale subjects. Subjects that scale upwards are generally those taken by academically talented students who do well in their other subjects as well. I_F

Whoever told you that is either a liar or misinformed. Neither your school ranking or your own subject rankings from last year will have any effect on your final HSC marks. They may give you a general idea of where everyone will wash up, but in no way will they impact on your marks. Rank-wise...

Some for series and sequences: 1. Show that (x+1) + (2x+4) + (3x+7) + ... is an arithmetic series. Hence find the sum of the first 50 terms of the series. 2. A couple borrow $140 000 to buy a house. Interest is charged on the loan at 15% per annum, and the loan (including interest) is to...

It seems as though you have a serious spyware infestation. Firstly, uninstall that Craggle thing, delete the installer, and never ever ever mention it here again. Then follow this guide to getting rid of spyware (scroll down a little to the appropriate answer). I_F

Do a forced refresh (Ctrl-F5 on the main page) and that should do it. If not, clear your cache, and that will definitely do it. I_F

I want to have the freedom to choose the uni course I want to do, so that means I need the best mark I can get to maximise my choices. Good on you, by the way, for choosing to complete your HSC. By the sounds of it, you seem ready to give it your best shot, and that's what's important. If you...

Invites mean you send an email to another user "inviting" them to join the trial. It gives them a specific link to get the software. I got a few for Windows Live Mail, but they didn't seem to work when I sent them. Oh well. I_F

Go to your User CP (link in the top left hand corner), then go to "Edit Options". Under "Private Messaging", you need to enable private messaging. :) Nice to see you back, pLuvia, and top result, Dreamerish!. :D I_F

Because SAM converts an aligned mark into a scaled mark, not a raw mark into a scaled mark. I_F

You don't have to do an extension to get a high UAI. What you do have to do is do well across all your subjects, regardless of what they are. Doing an extension does not equal an automatic high UAI. Working consistently all year at all your subjects and doing extremely well in the exam does...

The aligned mark is the mark that's been aligned by the Board of Studies to the "standards packages" for each subject. Firstly, the papers are marked and the raw marks (straight from the exam papers) are obtained. Then, aligning takes place. It's basically where people look over the raw marks...

Aren't they, by definition, the smartass/nerd? :p I_F

Bad. Very, very bad. You don't want to do anything, you can't motivate yourself to do anything, and you get a "**** it all" attitude. I was so close to burnout at the end of last year due to a massively busy Term 3, holidays, and Term 4, and I just didn't want to work at all. I was mentally...

I just went and bought some Papermate gel ink pens. If I write too small, the writing gets really messy, but larger, and they're very smooth. I likey. :) I_F

Just for that, I'll add you too. Just remember that chemists aren't mathematicians, so more often than not you'll need to write out a sentence reason rather than a mathematical one. :p It sounds like you're well-set for a good year of Chemistry. Best of luck for Year 11. :) I_F

It's being fixed. The board isn't handling the special symbols particularly well at the moment due to the upgrade, but the admins are on it. :) Next question: For the parabola x2 + 2x + 28y - 111 = 0, find the coordinates of its vertex and focus, and the equations of its directrix and axis...

8.0g is correct. The mass of the products in any chemical reaction is equal to the mass of the reactants, so the mass of 2Q + R must equal the mass of S+3T. There are still exactly the same number of atoms present before and after the reaction. The mass of the products in any chemical reaction...

No problemo. Thanks for sticking it out. We got it together. :p I_F

That's what I just thought of. I'm reading through Keypad's answer from above, and I realise why. We need split up the integral - from 0 to 1, it's we use x2 = y (there's your bottom half), and from 1 to 2, it's x2 = 2-y (there's the top half). That fills the full integral, with limits from 0 to...