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I don't think 60 raw = E4.. maybe 7x+

let radius = r OB = (r-3) AB = (1/2)AC = 5 OA^2 = OB^2 + AB^2 r^2 = r^2 - 6r + 9 + 25 r = 34 r = 34/6 = 17/3

(n-5)! = (n-6)!*(n-5)

the coefficient of x^5 is 3^(n-5)*2^5 * (n C 5) that for x^6 is 3^(n-6)*2^6*(n C 6) since they are equal, divide the first by second, and you should get 1 so [3(n C 5)]/[2(n C 6)] = 1 3n!/5!(n-5)! = 2n!/6!(n-6)! simplifying 2(n-5) = 18 n-5 = 9, n=14

because you get more answers here

The difficulty to attain a mark increases exponentially, 60 raw is quite decent...

measure with CRO

maybe you can prove that it is impossible to link each divergent series to an unique convergent series?

let u = cos(x) then du = -sin(x) dx so your integral becomes integrate [1/2 -> 1] -3u^2 du = -u^3 (evaluate with limits) = -7/8

lol at maniac guy's signature

Re: Re: Integration Hmm incorrect :P

General principles If a piece of glassware is used to MEASURE volume of something, then it should be washed with the solution that is intented to be measured. If a piece of glassware is used to hold a MEASURED AMOUNT of something, it should only be washed with distilled water NOT with...

While you are on it find: Integrate [0->1] [x(1-x)]^4/(x^2 + 1) dx and hence show that pi is not 22/7

graph y=x y=x^2 (x squared) y=x^3 y=x^4 y=x^5 more if you have time. notice if you rotate the graphs of the odd powered x's about the origin for 180 degrees, you get the same graph. That's basically what odd functions are, they are symmetric about the origin. now look at the...

define tan(x), then I will give you a proof

follow what they give you, (they shouldn't be giving you false numbers) it's actually about 1/250 for acetic at that conc. if I haven't forgot my chemistry (4 months since I read on it) oh and, the extent of dissociation is related to concentration

IUPAC (prefered) name is styrene.. I don't think they can mark you wrong if you said styrene for systematic name

Dicksmith if you don't mind the price Really depends on the quality and scale of your motor. if you school has a TAS (tech and applied studies) workshop with metalwork/wood work room you should try to get permission to use it

first P(x) = (x-a)(x-b)Q(x) + (cx+d) for some cx+d then: P(a) = a^2 P(b)= b^2 by the remainder theorem. so if you ca+d=a^2 cb +d = b^2 subtract the bottom equation from the one above c(a-b) = a^2 - b^2 c= a+b solve for d by substituting in ca + d = a^2 a^2 + ab...

yea.. just a minor point, f:r->r+ is not well defined because f(0) is not in the codomain