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Cough* Cough* WAR COMMUNISM!

Recall V=\pi\int^{a}_{b}{y^{2}}\, dy You can integrate separately for the corresponding areas by letting: y^2=x^4=\pi\int^{1}_{0}{y^{2}_1}\, dy y^2=[(x-2)^2]^2=\pi\int^{2}_{1}{y^{2}_1}\, dy \pi\int^{1}_{0}{y^{2}_1}\, dy+\pi\int^{2}_{1}{y^{2}_2}\, dy

You need a minimum of 12 credit points of mathematics for your first year of BSc. You do not need to do mathematics to transfer to science but it would definitely be an advantage as you can have more credits transferred. Credits are similar to 'units' from HSC where each subject is usually worth...

Prerequisite is a minimum mark of 65 in HSC physics. University physics is almost all calculations, thus making a huge portion of HSC physics irrelevant whilst emphasizing more on your mathematical background. Plus, the course outline says PHYS1001 should be studied concurrently with MATH1XX1...

He should maintain at least a credit average in his first year.

Pretty much all the ones that are listed on the USU website requires an ACCESS card to join.

Find y-axis x^7=-1;x=1 A function where the highest degree is the only variable f(x)=x^{n}+c (where n is odd), the curve usually looks similar the cubic function {f(x)=x^{3} for \{n{\in}\mathbb{R}|n{\geq}3\} expect the "horizontal point of inflection" looks longer depending on the degree. The...

Mine originally had 9-5 no break when I first got it. Just change to another time if available.

Let u=2^{-x} and let v=lnx u'=-2e^{-x};v'=\frac{1}{x} The product rule: \frac{d(f(u)g(v))}{dx}=u'v+v'u Hence: \frac{2e^-{x}}{x}-2lnxe^{-x}

You can write it as -1<tanx<1?

13' Air has the longer battery life ~12hours

I did dy because we are integrating with respect to y. You need to do this in order to find the area along the y-axis \int^{2}_{1}y^\frac{-1}{2}\, dy = \frac{y^\frac{-1}{2}}{\frac{1}{2}} = [2\sqrt{y} ]^2_1

Q4. y=\frac{1}{x^2} becomes \frac{1}{\sqrt{y}} Thus, \int^{2}_{1}\frac{1}{\sqrt{y}} \, dy self explanatory from there on; Q6. A1, \int^{2}_{1}x^2 \, dx = [\frac{x^3}{3}]^{2}_{1}=\frac{7}{3} A2, x^2=y = x=\sqrt{y} = \int^{4}_{1}{\sqrt{y} }\, dy = [\frac{2(y^{\frac{5}{3}})}{3}]^4_1 =\frac{14}{3}...

Maybe you should try to reattempt the question if you haven't, then post if you're have difficulties.

Because you're adding the two areas together

In before this goes for 3 pages: \int^{0}_{-1} -x^2 + 3x + 2 \, dx+\int^{2}_{0} -x^2 + 3x + 2 \, dx = [\frac{-x^3}{3}+\frac{x^2}{2}+2x]^{0}_{-1}+[\frac{-x^3}{3}+\frac{x^2}{2}+2x]^{2}_{0} = \frac{7}{6}+\frac{10}{3}=4\frac{1}{2}

It does depend on your external + internal marks and also how well the subject aligns during your HSC year. To get an idea for previous years, have a look at the raw marks database: http://community.boredofstudies.org/461/atar-hsc-marks/324426/updated-raw-marks-database-sortable-excel-file.html

Couldn't be bothered to do anything fancy, grew mould on bread. Measured temp and humidity with a hygrometer, ended up growing penicillin (or something similar) that killed off the surrounding mould.

You can do a bridging course for 2U or do MATH130 in the first semester before math135 (which has a prerequisite of a B4 in 2U) and physics.

You can start 2nd semester of they have it (usyd usually only has engineering starting first semester though), otherwise yes, it is VERY calculus heavy. If you look at the CUSP you have 4 math course, 2 (differential and integral) calculus course not to mention PHYS1001 and engg1802 which also...